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Question

A train travels 165 km in 95 minutes and remaining 73 km in 1500 seconds. What is the average speed of the train?

The correct answer is

119 km/hour

Understanding Average Speed

The question asks us to find the average speed of a train. Average speed is calculated by dividing the total distance traveled by the total time taken.

The formula for average speed is:

\(\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}\)

Calculating Total Distance

The train travels in two parts:

  • First part: 165 km
  • Second part: 73 km

The total distance is the sum of these two distances.

\(\text{Total Distance} = 165 \text{ km} + 73 \text{ km}\)

\(\text{Total Distance} = 238 \text{ km}\)

Calculating Total Time

The time taken is given in two different units:

  • First part: 95 minutes
  • Second part: 1500 seconds

To find the total time, we need to convert both time durations into the same unit. Since the options for average speed are in km/hour, it is best to convert the time into hours.

Converting Time 1 (95 minutes) to Hours

There are 60 minutes in 1 hour. To convert minutes to hours, we divide by 60.

\(\text{Time}_1 = 95 \text{ minutes} = \frac{95}{60} \text{ hours}\)

\(\text{Time}_1 = \frac{19}{12} \text{ hours}\)

Converting Time 2 (1500 seconds) to Hours

There are 60 seconds in 1 minute and 60 minutes in 1 hour. So, there are \(60 \times 60 = 3600\) seconds in 1 hour. To convert seconds to hours, we divide by 3600.

\(\text{Time}_2 = 1500 \text{ seconds} = \frac{1500}{3600} \text{ hours}\)

\(\text{Time}_2 = \frac{15}{36} \text{ hours}\)

We can simplify the fraction \(\frac{15}{36}\) by dividing both numerator and denominator by their greatest common divisor, which is 3.

\(\text{Time}_2 = \frac{15 \div 3}{36 \div 3} \text{ hours} = \frac{5}{12} \text{ hours}\)

Calculating Total Time in Hours

Total time is the sum of Time 1 and Time 2.

\(\text{Total Time} = \text{Time}_1 + \text{Time}_2\)

\(\text{Total Time} = \frac{19}{12} \text{ hours} + \frac{5}{12} \text{ hours}\)

\(\text{Total Time} = \frac{19 + 5}{12} \text{ hours}\)

\(\text{Total Time} = \frac{24}{12} \text{ hours}\)

\(\text{Total Time} = 2 \text{ hours}\)

Calculating Average Speed

Now we have the total distance and the total time in the required units (km and hours).

  • Total Distance = 238 km
  • Total Time = 2 hours

Using the average speed formula:

\(\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{238 \text{ km}}{2 \text{ hours}}\)

\(\text{Average Speed} = 119 \text{ km/hour}\)

The average speed of the train is 119 km/hour.

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Important Questions from Motion in a Straight Line

  1. Which of the following examples represents motion along a straight line?
  2. Ram records the odometer readings of his car for the distance covered from 2000 km at the start of his journey and 2400 km at the end of the journey after 8 hours. What is the average speed of the car?

  3. A body moves along a straight line with displacement \(s = 4t^2 + 2ts =4t^2+2ts=4t^2+2t\) (in m, t in s). Its instantaneous acceleration is:

  4. The area under a velocity-time graph between two instants represents:

  5. A body is dropped freely from a height 'X' m. If tit takes Y seconds to reach the ground. The time it takes to reach half of the height of the tower is (Take g = 10m/s2)

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