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Question

A swimmer swims downstream from point A to point B in 4 hours. It covers the same distance upstream in 5 hours. If the speed of the stream is 2 km/h, what is the distance between A and B:

The correct answer is

80 km

Solving Swimmer Downstream and Upstream Problems

This problem involves understanding how the speed of the stream affects the speed of a swimmer moving with or against the current. We need to use the concepts of relative speed to find the distance between two points.

Understanding Relative Speed in Water

  • When the swimmer moves downstream, the speed of the stream adds to the swimmer's speed in still water. This is because the stream is helping the swimmer move faster.
  • When the swimmer moves upstream, the speed of the stream subtracts from the swimmer's speed in still water. This is because the stream is resisting the swimmer's movement.

Setting up the Equations

Let's define the variables:

  • Let $s$ be the speed of the swimmer in still water (in km/h).
  • Let $v$ be the speed of the stream (in km/h). We are given $v = 2$ km/h.
  • Let $d$ be the distance between point A and point B (in km).

We know that Distance $=$ Speed $\times$ Time.

  • Downstream: The swimmer travels from A to B in 4 hours.
    • Downstream speed = Speed of swimmer in still water $+$ Speed of stream
    • Downstream speed = $s + v = s + 2$ km/h
    • Distance $d = (s + 2) \times 4$
  • Upstream: The swimmer travels from B to A (the same distance) in 5 hours.
    • Upstream speed = Speed of swimmer in still water $-$ Speed of stream
    • Upstream speed = $s - v = s - 2$ km/h
    • Distance $d = (s - 2) \times 5$

Since the distance $d$ is the same in both cases, we can set the two expressions for $d$ equal to each other:

$(s + 2) \times 4 = (s - 2) \times 5$

Solving for the Swimmer's Speed

Now, we solve this equation to find the value of $s$, the speed of the swimmer in still water:

$4s + 8 = 5s - 10$

To solve for $s$, we can rearrange the terms:

$8 + 10 = 5s - 4s$

$18 = s$

So, the speed of the swimmer in still water is 18 km/h.

Calculating the Distance

Now that we have the speed of the swimmer in still water ($s = 18$ km/h), we can use either the downstream or upstream equation for distance to find $d$.

Using the downstream equation:

$d = (s + 2) \times 4$

$d = (18 + 2) \times 4$

$d = 20 \times 4$

$d = 80$ km

Using the upstream equation (just to double-check):

$d = (s - 2) \times 5$

$d = (18 - 2) \times 5$

$d = 16 \times 5$

$d = 80$ km

Both calculations give the same distance, 80 km.

Summary of Steps

  1. Define variables for swimmer speed, stream speed, and distance.
  2. Write expressions for downstream speed (swimmer + stream) and upstream speed (swimmer - stream).
  3. Use the formula Distance = Speed $\times$ Time to write equations for the distance in both the downstream and upstream cases.
  4. Equate the two distance expressions since the distance is the same.
  5. Solve the resulting equation to find the swimmer's speed in still water.
  6. Substitute the swimmer's speed back into either the downstream or upstream distance equation to calculate the distance.
Concept Formula Values
Downstream Speed Speed of swimmer + Speed of stream $s + 2$ km/h
Upstream Speed Speed of swimmer - Speed of stream $s - 2$ km/h
Downstream Distance Downstream Speed $\times$ Downstream Time $(s + 2) \times 4$
Upstream Distance Upstream Speed $\times$ Upstream Time $(s - 2) \times 5$
Equating Distances $(s + 2) \times 4 = (s - 2) \times 5$ $s = 18$ km/h
Final Distance $(18 + 2) \times 4$ or $(18 - 2) \times 5$ $80$ km

The distance between A and B is 80 km.

Revision Table: Swimmer Speed Concepts

Term Definition Formula
Speed of Swimmer in Still Water ($s$) The speed at which the swimmer moves without the influence of the current. -
Speed of Stream ($v$) The speed of the flowing water. -
Downstream Speed The effective speed when moving with the current. $s + v$
Upstream Speed The effective speed when moving against the current. $s - v$
Relationship If speeds are $S_D$ (downstream) and $S_U$ (upstream), then $s = \frac{S_D + S_U}{2}$ and $v = \frac{S_D - S_U}{2}$. -

Additional Information: Speed, Time, and Distance Problems

Problems involving relative speed in water (like swimmers or boats in streams) are common applications of the basic speed, time, and distance formula ($D = S \times T$).

Key points to remember:

  • Always identify the speed of the object in still water and the speed of the stream.
  • Remember that downstream speed is the sum of these two speeds, and upstream speed is the difference.
  • The distance traveled is often the same for the downstream and upstream journeys in these types of problems, allowing you to equate the distance expressions.
  • Be careful with units (km/h, meters/second, etc.) and ensure they are consistent throughout the calculation.

These problems often require setting up and solving linear equations, as demonstrated in the solution above.

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Important Questions from Boat and River

  1. If a boat travels with a speed of 12 km/hr in still water and the speed of stream is 3 km/hr, what would be the time taken (in hours) by boat to go 60 km downstream?
  2. A boat moves at a speed of 7 km/h in still water. The boat goes 40 km downstream and then 40 km upstream. It is observed that the total time taken for this journey is 560 minutes less than the time it would take if the speed of the stream were 2 km/h faster. What is the initial speed (in km/h) of the stream?
  3. A boat travels 120 km downstream in 6 hours and 120 km upstream in 10 hours. The speed of the current is 4 km/hr. What is the speed of the boat in still water?
  4. Ashok rows 43.5 kmph in still water. If the river is running at 14.5 kmph, it takes him 90 minutes to row to a place and back. How far is the place from the starting point? (In km)
  5. Aman can go downstream thrice as fast as he can go upstream between two specific points on a river. If the river flows at 8 kmph, what is the speed of the boat in still water (in kmph) ?
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