A swimmer swims downstream from point A to point B in 4 hours. It covers the same distance upstream in 5 hours. If the speed of the stream is 2 km/h, what is the distance between A and B:
80 km
This problem involves understanding how the speed of the stream affects the speed of a swimmer moving with or against the current. We need to use the concepts of relative speed to find the distance between two points.
Let's define the variables:
We know that Distance $=$ Speed $\times$ Time.
Since the distance $d$ is the same in both cases, we can set the two expressions for $d$ equal to each other:
$(s + 2) \times 4 = (s - 2) \times 5$
Now, we solve this equation to find the value of $s$, the speed of the swimmer in still water:
$4s + 8 = 5s - 10$
To solve for $s$, we can rearrange the terms:
$8 + 10 = 5s - 4s$
$18 = s$
So, the speed of the swimmer in still water is 18 km/h.
Now that we have the speed of the swimmer in still water ($s = 18$ km/h), we can use either the downstream or upstream equation for distance to find $d$.
Using the downstream equation:
$d = (s + 2) \times 4$
$d = (18 + 2) \times 4$
$d = 20 \times 4$
$d = 80$ km
Using the upstream equation (just to double-check):
$d = (s - 2) \times 5$
$d = (18 - 2) \times 5$
$d = 16 \times 5$
$d = 80$ km
Both calculations give the same distance, 80 km.
| Concept | Formula | Values |
|---|---|---|
| Downstream Speed | Speed of swimmer + Speed of stream | $s + 2$ km/h |
| Upstream Speed | Speed of swimmer - Speed of stream | $s - 2$ km/h |
| Downstream Distance | Downstream Speed $\times$ Downstream Time | $(s + 2) \times 4$ |
| Upstream Distance | Upstream Speed $\times$ Upstream Time | $(s - 2) \times 5$ |
| Equating Distances | $(s + 2) \times 4 = (s - 2) \times 5$ | $s = 18$ km/h |
| Final Distance | $(18 + 2) \times 4$ or $(18 - 2) \times 5$ | $80$ km |
The distance between A and B is 80 km.
| Term | Definition | Formula |
|---|---|---|
| Speed of Swimmer in Still Water ($s$) | The speed at which the swimmer moves without the influence of the current. | - |
| Speed of Stream ($v$) | The speed of the flowing water. | - |
| Downstream Speed | The effective speed when moving with the current. | $s + v$ |
| Upstream Speed | The effective speed when moving against the current. | $s - v$ |
| Relationship | If speeds are $S_D$ (downstream) and $S_U$ (upstream), then $s = \frac{S_D + S_U}{2}$ and $v = \frac{S_D - S_U}{2}$. | - |
Problems involving relative speed in water (like swimmers or boats in streams) are common applications of the basic speed, time, and distance formula ($D = S \times T$).
Key points to remember:
These problems often require setting up and solving linear equations, as demonstrated in the solution above.
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