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Question

A sum when invested at the rate of 12.5% simple interest per annum, amounts to ₹7,500 after 2 years. The simple interest (in ₹) for the given time period is:

The correct answer is
1,500

Simple Interest Calculation Steps

This problem asks us to find the simple interest earned over a specific period, given the final amount, the annual interest rate, and the time duration. We need to work backward from the amount to find the original principal and then calculate the interest.

Given Investment Details

Here's what we know from the question:

  • Interest Rate (R) = 12.5% per annum
  • Amount after 2 years (A) = ₹7,500
  • Time Period (T) = 2 years

Interest Formulas Explained

To solve this, we use the basic formulas for simple interest:

  • The formula for the final amount (A) is the sum of the principal (P) and the simple interest (SI):

    $A = P + SI$

  • The formula for simple interest (SI) is:

    $SI = \frac{P \times R \times T}{100}$

We can combine these formulas. Substituting the SI formula into the Amount formula:

$A = P + \frac{P \times R \times T}{100}$

Factoring out P, we get:

$A = P \left( 1 + \frac{R \times T}{100} \right)$

Calculating the Principal Amount

First, we need to find the original principal amount (P). We can rearrange the combined formula to solve for P:

$P = \frac{A}{ \left( 1 + \frac{R \times T}{100} \right) } $

Now, let's plug in the given values:

  • $A = 7500$
  • $R = 12.5$
  • $T = 2$

Calculate the term in the denominator:

$ \frac{R \times T}{100} = \frac{12.5 \times 2}{100} = \frac{25}{100} = 0.25 $

Now substitute this back into the formula for P:

$P = \frac{7500}{1 + 0.25} = \frac{7500}{1.25} $

To make the division easier, we can write 1.25 as a fraction $\frac{5}{4}$:

$P = \frac{7500}{5/4} = 7500 \times \frac{4}{5} $

$P = \frac{7500 \times 4}{5} = 1500 \times 4 = 6000 $

So, the principal amount invested was ₹6,000.

Determining the Simple Interest

Now that we have the principal amount (P = ₹6,000), we can calculate the simple interest (SI) using the SI formula:

$SI = \frac{P \times R \times T}{100}$

Substitute the values:

$SI = \frac{6000 \times 12.5 \times 2}{100}$

$SI = \frac{6000 \times 25}{100}$

$SI = 60 \times 25$

$SI = 1500$

The simple interest earned for the 2-year period is ₹1,500.

Final Answer Verification

The calculated simple interest is ₹1,500. This matches one of the options provided.

Principal (P) = ₹6,000

Interest (SI) = ₹1,500

Amount (A) = P + SI = ₹6,000 + ₹1,500 = ₹7,500. This confirms our calculation is correct.

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Important Questions from Simple Interest

  1. How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest ?

  2. Nirav and Mehul borrowed Rs.4000 and Rs.5000 respectively for 2.5 years at the rate of x% per annum. Mehul paid Rs 125 more interest than Nirav. Find x.

  3. If the interest on a sum of Rs.1200 is more than the interest on Rs.1000 by Rs.120 in three years, then what is the rate of interest per annum?.

  4. The difference between the simple interest received from two banks on Rs. 500 for two years is Rs. 2.50. What is the difference between their rates?

  5. A sum of Rs.1200 becomes Rs.1560 at a rate of simple interest in 3 years. In how many years will the sum of Rs.800 amount to Rs.1120 at the same rate of simple interest?

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