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Question

A sum when invested at the rate of 12.5% simple interest per annum, amounts to ₹7,500 after 2 years. The simple interest (in ₹) for the given time period is:

The correct answer is
1,500

Simple Interest Calculation Steps

This problem asks us to find the simple interest earned over a specific period, given the final amount, the annual interest rate, and the time duration. We need to work backward from the amount to find the original principal and then calculate the interest.

Given Investment Details

Here's what we know from the question:

  • Interest Rate (R) = 12.5% per annum
  • Amount after 2 years (A) = ₹7,500
  • Time Period (T) = 2 years

Interest Formulas Explained

To solve this, we use the basic formulas for simple interest:

  • The formula for the final amount (A) is the sum of the principal (P) and the simple interest (SI):

    $A = P + SI$

  • The formula for simple interest (SI) is:

    $SI = \frac{P \times R \times T}{100}$

We can combine these formulas. Substituting the SI formula into the Amount formula:

$A = P + \frac{P \times R \times T}{100}$

Factoring out P, we get:

$A = P \left( 1 + \frac{R \times T}{100} \right)$

Calculating the Principal Amount

First, we need to find the original principal amount (P). We can rearrange the combined formula to solve for P:

$P = \frac{A}{ \left( 1 + \frac{R \times T}{100} \right) } $

Now, let's plug in the given values:

  • $A = 7500$
  • $R = 12.5$
  • $T = 2$

Calculate the term in the denominator:

$ \frac{R \times T}{100} = \frac{12.5 \times 2}{100} = \frac{25}{100} = 0.25 $

Now substitute this back into the formula for P:

$P = \frac{7500}{1 + 0.25} = \frac{7500}{1.25} $

To make the division easier, we can write 1.25 as a fraction $\frac{5}{4}$:

$P = \frac{7500}{5/4} = 7500 \times \frac{4}{5} $

$P = \frac{7500 \times 4}{5} = 1500 \times 4 = 6000 $

So, the principal amount invested was ₹6,000.

Determining the Simple Interest

Now that we have the principal amount (P = ₹6,000), we can calculate the simple interest (SI) using the SI formula:

$SI = \frac{P \times R \times T}{100}$

Substitute the values:

$SI = \frac{6000 \times 12.5 \times 2}{100}$

$SI = \frac{6000 \times 25}{100}$

$SI = 60 \times 25$

$SI = 1500$

The simple interest earned for the 2-year period is ₹1,500.

Final Answer Verification

The calculated simple interest is ₹1,500. This matches one of the options provided.

Principal (P) = ₹6,000

Interest (SI) = ₹1,500

Amount (A) = P + SI = ₹6,000 + ₹1,500 = ₹7,500. This confirms our calculation is correct.

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Important Questions from Simple Interest

  1. Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?

  2. What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?

  3. If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)

  4. On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?

  5. A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?

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