A sum when invested at the rate of 12.5% simple interest per annum, amounts to ₹7,500 after 2 years. The simple interest (in ₹) for the given time period is:
This problem asks us to find the simple interest earned over a specific period, given the final amount, the annual interest rate, and the time duration. We need to work backward from the amount to find the original principal and then calculate the interest.
Here's what we know from the question:
To solve this, we use the basic formulas for simple interest:
$A = P + SI$
$SI = \frac{P \times R \times T}{100}$
We can combine these formulas. Substituting the SI formula into the Amount formula:
$A = P + \frac{P \times R \times T}{100}$
Factoring out P, we get:
$A = P \left( 1 + \frac{R \times T}{100} \right)$
First, we need to find the original principal amount (P). We can rearrange the combined formula to solve for P:
$P = \frac{A}{ \left( 1 + \frac{R \times T}{100} \right) } $
Now, let's plug in the given values:
Calculate the term in the denominator:
$ \frac{R \times T}{100} = \frac{12.5 \times 2}{100} = \frac{25}{100} = 0.25 $
Now substitute this back into the formula for P:
$P = \frac{7500}{1 + 0.25} = \frac{7500}{1.25} $
To make the division easier, we can write 1.25 as a fraction $\frac{5}{4}$:
$P = \frac{7500}{5/4} = 7500 \times \frac{4}{5} $
$P = \frac{7500 \times 4}{5} = 1500 \times 4 = 6000 $
So, the principal amount invested was ₹6,000.
Now that we have the principal amount (P = ₹6,000), we can calculate the simple interest (SI) using the SI formula:
$SI = \frac{P \times R \times T}{100}$
Substitute the values:
$SI = \frac{6000 \times 12.5 \times 2}{100}$
$SI = \frac{6000 \times 25}{100}$
$SI = 60 \times 25$
$SI = 1500$
The simple interest earned for the 2-year period is ₹1,500.
The calculated simple interest is ₹1,500. This matches one of the options provided.
Principal (P) = ₹6,000
Interest (SI) = ₹1,500
Amount (A) = P + SI = ₹6,000 + ₹1,500 = ₹7,500. This confirms our calculation is correct.
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