A sum of money of Rs. 2600.00 was lent out in two parts in such a way that the simple interest on the first part at 10% per annum for 5 years is the same as the interest of the second part at 9% per annum for 6 years. The part lent out at 10% is -
Rs. 1350
This question involves dividing a total sum of money into two parts and calculating the simple interest earned on each part. The key condition is that the simple interest from both parts is equal, even though the principal amounts, rates, and time periods are different.
We are given:
We need to find the amount lent out as the first part (at 10% per annum).
The formula for calculating Simple Interest (SI) is:
\( SI = \frac{P \times R \times T}{100} \)
Where:
Let the first part of the sum lent out at 10% be \( P_1 \). Let the second part of the sum lent out at 9% be \( P_2 \).
According to the question, the total sum is Rs. 2600.00. So, we have our first equation:
Equation 1: \( P_1 + P_2 = 2600 \)
Now, let's calculate the simple interest for each part:
The question states that the simple interest on the first part is the same as the interest on the second part:
Equation 2: \( SI_1 = SI_2 \)
\( \frac{50 P_1}{100} = \frac{54 P_2}{100} \)
Now we need to solve the two equations simultaneously to find the values of \( P_1 \) and \( P_2 \).
From Equation 2, we can simplify by multiplying both sides by 100:
\( 50 P_1 = 54 P_2 \)
We can divide both sides by 2 to simplify further:
\( 25 P_1 = 27 P_2 \)
From this relationship, we can express \( P_2 \) in terms of \( P_1 \):
\( P_2 = \frac{25 P_1}{27} \)
Now substitute this expression for \( P_2 \) into Equation 1:
\( P_1 + \frac{25 P_1}{27} = 2600 \)
To solve for \( P_1 \), find a common denominator (which is 27):
\( \frac{27 P_1}{27} + \frac{25 P_1}{27} = 2600 \)
\( \frac{27 P_1 + 25 P_1}{27} = 2600 \)
\( \frac{52 P_1}{27} = 2600 \)
Now, isolate \( P_1 \) by multiplying both sides by \( \frac{27}{52} \):
\( P_1 = 2600 \times \frac{27}{52} \)
We can simplify the calculation. \( 2600 = 52 \times 50 \). So, \( \frac{2600}{52} = 50 \).
\( P_1 = 50 \times 27 \)
Calculating the final value for \( P_1 \):
\( P_1 = 1350 \)
So, the part lent out at 10% per annum is Rs. 1350.
Although not asked, we can find the second part (\( P_2 \)) using Equation 1:
\( P_2 = 2600 - P_1 \)
\( P_2 = 2600 - 1350 \)
\( P_2 = 1250 \)
The second part lent out at 9% per annum is Rs. 1250.
Let's verify if the simple interest is indeed equal for both parts with \( P_1 = 1350 \) and \( P_2 = 1250 \).
Since \( SI_1 = SI_2 = 675 \), our calculation is correct.
The part lent out at 10% per annum is Rs. 1350.
Let's look at the given options:
| Option | Amount |
|---|---|
| 1 | Rs. 1250 |
| 2 | Rs. 1450 |
| 3 | Rs. 1150 |
| 4 | Rs. 1350 |
The calculated amount for the part lent at 10% is Rs. 1350, which matches option 4.
| Step | Description | Formula/Action |
|---|---|---|
| 1 | Define variables for the two principal amounts. | \(P_1\), \(P_2\) |
| 2 | Write the equation for the total sum. | \(P_1 + P_2 = \text{Total Sum}\) |
| 3 | Calculate Simple Interest for each part. | \(SI = \frac{P \times R \times T}{100}\) |
| 4 | Set the Simple Interests equal to each other. | \(SI_1 = SI_2\) |
| 5 | Solve the resulting equation to relate \(P_1\) and \(P_2\). | \(R_1 T_1 P_1 = R_2 T_2 P_2\) |
| 6 | Substitute the relationship into the total sum equation. | Solve for the unknown principal (\(P_1\) or \(P_2\)) |
| 7 | Calculate the final answer. | Result from Step 6 |
Simple interest is a method of calculating the interest charge on a loan or investment. It is the easiest interest method to calculate.
Simple interest differs from compound interest, where interest is calculated on the principal amount and also on the accumulated interest from previous periods.
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