A sum invested at the rate of 6% simple interest per annum grows to Rs. 1,13,880 in 5 years. What is the simple interest, If the same amount is invested for 8 years at the rate of 9% per annum?
Rs. 63,072
This problem requires us to first find the initial principal amount using the information given about the first investment scenario, and then calculate the simple interest for a second scenario using that same principal.
We are given that a sum grows to Rs. 1,13,880 in 5 years at a simple interest rate of 6% per annum. The amount (A) received at the end of the investment period is the sum of the principal (P) and the simple interest (SI) earned.
The formula for simple interest is:
\( SI = \frac{P \times R \times T}{100} \)
Where:
The formula for the amount is:
\( A = P + SI \)
Substituting the SI formula into the amount formula:
\( A = P + \frac{P \times R \times T}{100} \)
Given values for the first scenario:
Substituting these values into the amount formula:
\( 1,13,880 = P + \frac{P \times 6 \times 5}{100} \)
\( 1,13,880 = P + \frac{30P}{100} \)
\( 1,13,880 = P + 0.3P \)
\( 1,13,880 = 1.3P \)
Now, solve for P:
\( P = \frac{1,13,880}{1.3} \)
To make division easier, we can write 1.3 as \( \frac{13}{10} \):
\( P = \frac{1,13,880}{\frac{13}{10}} = 1,13,880 \times \frac{10}{13} \)
\( P = \frac{11,38,800}{13} \)
Performing the division:
\( 1138800 \div 13 \)
\( 113 \div 13 \approx 8 \) ( \( 13 \times 8 = 104 \) )
\( 113 - 104 = 9 \)
\( 98 \div 13 \approx 7 \) ( \( 13 \times 7 = 91 \) )
\( 98 - 91 = 7 \)
\( 78 \div 13 = 6 \) ( \( 13 \times 6 = 78 \) )
So, \( \frac{11,38,800}{13} = 87600 \)
The principal amount \(P = 87,600\).
Now we need to calculate the simple interest for the same principal amount \(P = 87,600\) invested for 8 years at a rate of 9% per annum.
Given values for the second scenario:
Using the simple interest formula:
\( SI = \frac{P \times R \times T}{100} \)
Substituting the values:
\( SI = \frac{87,600 \times 9 \times 8}{100} \)
\( SI = \frac{87,600 \times 72}{100} \)
Cancel out the zeros from 87,600 and 100:
\( SI = 876 \times 72 \)
Calculating the product:
\( 876 \times 72 \)
\( 876 \times (70 + 2) = 876 \times 70 + 876 \times 2 \)
\( 876 \times 70 = 61320 \)
\( 876 \times 2 = 1752 \)
\( SI = 61320 + 1752 \)
\( SI = 63072 \)
The simple interest for the second scenario is Rs. 63,072.
| Scenario | Principal (P) | Rate (R) | Time (T) | Amount (A) / Simple Interest (SI) |
|---|---|---|---|---|
| 1 (Finding P) | \(P\) | \(6\%\) | \(5\) years | \(A = 1,13,880\) |
| 2 (Finding SI) | \(87,600\) | \(9\%\) | \(8\) years | \(SI = ?\) |
| Concept | Formula |
|---|---|
| Simple Interest (SI) | \( SI = \frac{P \times R \times T}{100} \) |
| Amount (A) | \( A = P + SI \) or \( A = P \left( 1 + \frac{R \times T}{100} \right) \) |
| Principal (P) from Amount | \( P = \frac{A \times 100}{100 + (R \times T)} \) |
Simple interest is a method of calculating interest where the interest amount is fixed over the investment period. It is calculated only on the initial principal amount. This differs from compound interest, where interest is calculated on the principal amount plus any accumulated interest from previous periods.
Factors that influence the simple interest earned are:
Simple interest is commonly used for short-term loans and is easier to calculate compared to compound interest.
At what rate percent per annum will Rs. 7200 amount to Rs. 7938 in one year, if interest is compounded half yearly?
What is the compound interest (in Rs.) on a sum of Rs. 8192 for \(1 \frac{1}{4}\) years at 15% per annum, if interest is compounded 5-monthly ?
What is the difference (in Rs.) between the interests on Rs. 50,000 for one year at 8% per annum compounded half yearly and yearly?
A sum of money becomes Rs. 11,880 after 4 years and Rs. 17,820 after 6 years on compound interest, if the interest is compounded annually. What is the half of the sum (in Rs.)?
A sum invested at compound interest amounts to Rs. 7,800 in 3 years and Rs. 11,232 in 5 years. What is the rate per cent?