The problem involves interpreting a pie chart representing examination scores. We are given the central angle for Mathematics and the scores for Statistics and Economics. We need to find the score for Mathematics.
In a pie chart, the central angle is proportional to the value it represents. A full circle represents a total angle of $360^{\circ}$.
We are given:
The central angle for Mathematics ($180^{\circ}$) is exactly half of the total angle ($360^{\circ}$). This implies that the score for Mathematics must be half of the total score obtained across all three subjects.
The combined score for Statistics and Economics is $80 + 70 = 150$.
Since the Mathematics angle ($180^{\circ}$) represents half the pie chart, its score must account for the remaining portion not covered by Statistics and Economics *if* those two represented the other half. However, the calculation works differently: the angle $180^{\circ}$ is half the total $360^{\circ}$. Therefore, the Mathematics score ($M_{score}$) must be half of the total score ($Total_{score}$).
The scores for Statistics and Economics together amount to $150$. Let the Mathematics score be $M_{score}$. The total score is $Total_{score} = M_{score} + 80 + 70 = M_{score} + 150$.
Using the proportionality:
$ \frac{\text{Mathematics Angle}}{\text{Total Angle}} = \frac{\text{Mathematics Score}}{\text{Total Score}} $ $ \frac{180^{\circ}}{360^{\circ}} = \frac{M_{score}}{M_{score} + 150} $ $ \frac{1}{2} = \frac{M_{score}}{M_{score} + 150} $Cross-multiplying gives:
$ 1 \times (M_{score} + 150) = 2 \times M_{score} $ $ M_{score} + 150 = 2 M_{score} $Subtracting $M_{score}$ from both sides:
$ 150 = M_{score} $Alternatively, since the Mathematics angle is $180^{\circ}$, it represents $50\%$ of the total. The remaining subjects (Statistics and Economics) account for the other $180^{\circ}$ (the other $50\%$) of the pie chart. Their combined score is $80 + 70 = 150$. Because this combined score represents $50\%$ of the total score, the Mathematics score (representing the other $50\%$) must also be $150$.
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