A student pushes a 4 kg cart so that its velocity changes from 2 m/s to 6 m/s in 2 seconds. What is the magnitude of the force applied on the cart?
8 N
By Newton's second law, \(F = ma\).
Acceleration \(a = \frac{v - u}{t} = \frac{6 - 2}{2} = 2\) m/s².
Force \(F = 4 \times 2 = 8\) N.
Hence, the answer is 8 N.
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