This problem involves calculating the speed of a steamer in still water given its travel times downstream and upstream, and the speed of the stream.
We are given:
Let $d$ be the distance between the two ports.
Downstream distance: $d = (s + v) \times t_{down}$
Upstream distance: $d = (s - v) \times t_{up}$
Since the distance $d$ is the same:
$ (s + v) \times t_{down} = (s - v) \times t_{up} $
$ (s + 3) \times 6 = (s - 3) \times 8 $
$ 6s + 18 = 8s - 24 $
$ 18 + 24 = 8s - 6s $
$ 42 = 2s $
$ s = \frac{42}{2} $
$ s = 21 $
The speed of the steamer in still water is 21 km/h.
A boat goes 30 km upstream in 3 hours and downstream in 1 hour. How much time (in hours) will this boat take to cover 60 km in still water?
The speed of a motorboat in still water is 20 km/h. It travels 150 km downstream and then returns to the starting point. If the round trip takes a total of 16 hours, what is the speed (in km/h) of the flow of river?
The time taken by a boat to travel 13 km downstream is the same as time taken by it to travel 7 km upstream. If the speed of the stream is 3 km/h, then how much time (in hours) will it take to travel a distance of 44.8 km in still water?
A man can row a distance of 8 km downstream in a certain time and can row 6 km upstream in the same time. If he rows 24 km upstream and the same distance downstream in \(1\frac{3}{4}\) hours, then the speed (in km/h) of the current is:
A boat goes 27 km upstream and 33 km downstream in 6 hours. In the same time it can go 36 km upstream and 22 km downstream. How much time will it take to go 36 km upstream and 44 km downstream?