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Question

A shuttle loom having 1.75 m reed width is running at 180 rpm. The shuttle enters and leaves the shed at $120^\circ$ and $240^\circ$ angular positions of crankshaft, respectively. If length of the shuttle is 0.25 m, then the mean velocity (in m/s) of the shuttle within the shed is________.

Shuttle Loom Velocity Calculation

This solution calculates the mean velocity of a shuttle within the shed of a loom.

Loom Parameters

  • Reed Width (W): 1.75 m
  • Shuttle Speed: 180 rpm
  • Shuttle Entry Angle: 120°
  • Shuttle Exit Angle: 240°
  • Shuttle Length (L): 0.25 m

Calculating Time Interval

First, determine the time it takes for the crankshaft to complete one revolution and then calculate the specific time the shuttle is active within the shed.

  • Crankshaft speed = 180 revolutions per minute (rpm).
  • Convert speed to revolutions per second (rps):

    $ \text{Speed} = \frac{180 \text{ rev}}{60 \text{ s}} = 3 \text{ rps} $

  • Calculate the time period (T) for one revolution:

    $ T = \frac{1}{\text{Speed}} = \frac{1}{3} \text{ s} $

  • Determine the angle traversed by the crankshaft while the shuttle is active:

    $ \text{Angle traversed} = \text{Exit Angle} - \text{Entry Angle} = 240^\circ - 120^\circ = 120^\circ $

  • Calculate the time interval ($\Delta t$) the shuttle is active within the shed. This corresponds to the time taken for the crankshaft to rotate through the calculated angle:

    $ \Delta t = \frac{\text{Angle traversed}}{360^\circ} \times T = \frac{120^\circ}{360^\circ} \times \frac{1}{3} \text{ s} = \frac{1}{3} \times \frac{1}{3} \text{ s} = \frac{1}{9} \text{ s} $

Calculating Shuttle Distance

The total distance the shuttle effectively travels during this active period is the sum of the reed width and the shuttle's own length.

  • Effective distance (D) = Reed Width + Shuttle Length

    $ D = W + L = 1.75 \text{ m} + 0.25 \text{ m} = 2.0 \text{ m} $

Calculating Mean Velocity

Finally, calculate the mean velocity using the effective distance and the time interval.

  • Mean Velocity = Distance / Time

    $ V_{\text{mean}} = \frac{D}{\Delta t} = \frac{2.0 \text{ m}}{1/9 \text{ s}} = 2.0 \times 9 \text{ m/s} = 18.0 \text{ m/s} $

The calculated mean velocity is 18.0 m/s, which falls within the expected range.

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Important Questions from FABR Shuttle Looms and Shuttleless Looms

  1. Profile reed is used in
  2. In a projectile weaving machine, the projectile travels through the shed at an average speed of $24$ m/s taking $2/3^{rd}$ of the loom cycle. If the efficiency of the weaving machine is $90\%$, the weft insertion rate (m/min) is (answer in integer) _________
  3. Match the looms listed in Group I with the corresponding components given in Group II. The correct option is
    Group IGroup II
    P. Multiphase1. Matched cam
    Q. Projectile2. Profile reed
    R. Air-jet3. Crank shaft
    S. Shuttle4. Weaving rotor
  4. In a loom, seven-wheel take-up motion is
  5. The diameter and length of torsion rod used in a projectile loom are increased by 5% and 20%, respectively. If the torque required to twist the rod increases by X%, then the value of X, accurate to two decimal places, is_______.

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