The flow condition in an open channel, like a river, is determined by comparing the flow velocity to the speed of a small gravity wave. This comparison is quantified using the Froude number ($Fr$).
The Froude number ($Fr$) is calculated as:
$ Fr = \frac{V}{\sqrt{g \cdot L_h}} $
For a wide rectangular channel, the hydraulic depth ($L_h$) is approximately equal to the flow depth ($D$). In this problem:
The flood plain width ($2 \text{ km}$) is significantly larger than the channel depth and typically does not directly influence the Froude number calculation for the main channel flow unless specified otherwise.
Substitute the values into the formula:
$ Fr = \frac{2 \text{ ms}^{-1}}{\sqrt{9.81 \text{ ms}^{-2} \cdot 10 \text{ m}}} $
$ Fr = \frac{2}{\sqrt{98.1}} $
$ Fr \approx \frac{2}{9.9045} $
$ Fr \approx 0.2019 $
The calculated Froude number determines the flow condition:
Since $Fr \approx 0.2019$, which is less than 1, the flow condition is sub-critical.
Read the following statements and choose the CORRECT answer.
I. The suspended sediment concentration in rivers is supply-limited rather than hydraulically-limited, when
II. Much suspended material is contributed by overland flow from hillslope erosion
III. Suspended material is entirely derived by turbulent diffusion from the channel bed
Match the basin types A, B and C with the hydrograph patterns P, Q and R
| Basin types | Hydrograph pattern | ||
| A. | ![]() | P. | ![]() |
| B. | ![]() | Q. | ![]() |
| C. | ![]() | R. | ![]() |
Hydraulic gradient beneath A and B during rainy and dry seasons will
Identify the correct sequence of freshwate abundance on the Earth.(GP = Glaciers and Polar ice; A = Atmosphere; LR = Lakes and Rivers; UW = Underground Water)