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Question

A ring counter with 5 flip-flops will have:

The correct answer is

5 states

This question asks us to determine the total number of unique states in a ring counter that utilizes 5 flip-flops.

Understanding Ring Counters

A ring counter is a specific type of sequential logic circuit. It's essentially a shift register where the output of the last flip-flop is connected back to the input of the first flip-flop. This feedback loop creates a circulating pattern of '1's and '0's.

States in a 5 Flip-Flop Ring Counter

In a standard ring counter configuration with n flip-flops, the counter cycles through n unique states. Each state typically has only one flip-flop set to '1' (or '0') while the rest are in the other state. The single '1' bit then shifts from one flip-flop to the next in each clock cycle.

For a ring counter with 5 flip-flops ($n=5$):

  • The initial state could be: 10000
  • After the first clock pulse: 01000
  • After the second clock pulse: 00100
  • After the third clock pulse: 00010
  • After the fourth clock pulse: 00001

After the fifth clock pulse, the '1' shifts back to the first flip-flop, returning the counter to the initial state (10000).

Therefore, there are exactly 5 distinct states that this type of ring counter can achieve.

Analyzing Other Options

  • 32 states: This would correspond to $2^5$, which is the number of states possible if each flip-flop could be independently set to 0 or 1, typical for a general asynchronous or synchronous counter without specific feedback loops like a ring counter.
  • 10 states: This number of states ($2n$) is characteristic of a Johnson counter (or twisted ring counter), where the inverted output of the last flip-flop is fed back to the input of the first. The question implies a standard ring counter.
  • Infinite: Counters operate in cycles and do not have infinite states.

Based on the standard definition of a ring counter, a setup with 5 flip-flops results in 5 unique states.

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Important Questions from Flip Flops and Counters

  1. Race around condition can be removed by using the combination of:

  2. A JK flip flop with J = K = 1 has a 100 kHz clock input. The Q output is

  3. A 4 bit counter is used to count form 0, 1, 2 …. n. Value of ‘n’ is

  4. Counter design can be implemented by:

  5. A. Design of synchronous counter is difficult as compared to asynchronous counter. 

    B. Digital counter are used for counting the pulses/events. 

    C. Counter are the combination circuits. 

    D. In Asynchronous counter, the same clock pulse can be applied to all the flip-flops. 

    Choose the correct answer from the options given below:

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