A real square matrix A is called skew-symmetric if
AT = -A
In linear algebra, a real square matrix is a matrix with an equal number of rows and columns, where all its elements are real numbers. Matrices can possess various special properties, and one such property defines them as skew-symmetric. Understanding these specific matrix properties is a fundamental aspect of matrix theory and linear algebra.
Before delving into the definition of a skew-symmetric matrix, let's first clarify the concept of a matrix transpose. The transpose of a matrix $A$, often denoted as $A^T$ (or $A'$), is formed by simply interchanging its rows and columns. If we consider a matrix $A$ where its elements are $a_{ij}$ (meaning the element in the $i$-th row and $j$-th column), then the corresponding element in its transpose $A^T$ will be $a_{ji}$.
For example, if we have a $2 \times 2$ matrix:
| $A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}$ |
Then its transpose $A^T$ would be:
| $A^T = \begin{pmatrix} a & c \\ b & d \end{pmatrix}$ |
A real square matrix $A$ is formally defined as skew-symmetric if its transpose is equal to the negative of the original matrix. This specific condition is mathematically represented as:
\(A^T = -A\)
This definition implies that for every element $a_{ij}$ located in the $i$-th row and $j$-th column of matrix $A$, the corresponding element $a_{ji}$ in the transpose $A^T$ must be equal to the negative of $a_{ij}$. Therefore, the relationship $a_{ji} = -a_{ij}$ must hold true for all possible values of $i$ and $j$.
An important implication of this matrix definition is that all the diagonal elements of a skew-symmetric matrix must be zero. This is because for diagonal elements, where $i = j$, the condition becomes $a_{ii} = -a_{ii}$. This equation simplifies to $2a_{ii} = 0$, which means $a_{ii} = 0$.
Consider an example of a $3 \times 3$ skew-symmetric matrix:
| $A = \begin{pmatrix} 0 & -2 & 3 \\ 2 & 0 & -1 \\ -3 & 1 & 0 \end{pmatrix}$ |
Let's compute its transpose $A^T$:
| $A^T = \begin{pmatrix} 0 & 2 & -3 \\ -2 & 0 & 1 \\ 3 & -1 & 0 \end{pmatrix}$ |
Now, let's calculate the negative of matrix $A$, which is $-A$:
| $-A = \begin{pmatrix} -(0) & -(-2) & -(3) \\ -(2) & -(0) & -(-1) \\ -(-3) & -(1) & -(0) \end{pmatrix} = \begin{pmatrix} 0 & 2 & -3 \\ -2 & 0 & 1 \\ 3 & -1 & 0 \end{pmatrix}$ |
As illustrated by this example, $A^T = -A$, which verifies that this matrix $A$ is indeed a skew-symmetric matrix.
Let's evaluate each of the provided options in the context of standard matrix properties and definitions:
Based on the established definitions of various matrix types and their characteristic properties, a real square matrix $A$ is officially classified as skew-symmetric if and only if its transpose is equivalent to the negative of the matrix itself, which is formally written as \(A^T = -A\).
If A = \(\left[\begin{array}{cc}2 & −3 \\3 & 5\end{array}\right]\), then which of the following statements are correct?
A. A is a square matrix
B. A−1 exists
C. A is a symmetric matrix
D. |A| = 19
E. A is a null matrix
Choose the correct answer from the options given below.
If A is Square Matrix of order 3, then product of A and its transpose is
What is the transformation matrix M that transforms a square in the xy-plane defined by (1, 1) T, (-1, 1) T, (-1, -1) T and (1, -1) T to a parallelogram whose corresponding vertices are (2, 1) T, (0, 1) T, (-2, -1) T and (0, -1) T?
Let \(A = \left[ {\begin{array}{*{20}{c}} 1&1&0\\ 0&1&0\\ 1&1&0\\ 0&0&1 \end{array}} \right]\) and \(B = \left[ {\begin{array}{*{20}{c}} 1&0&0&0\\ 0&1&1&0\\ 1&0&1&1\\ \end{array}} \right]\) Find the boolean product A ⊙ B of the two matrices.