A real square matrix A is called skew-symmetric if
AT = -A
In linear algebra, a real square matrix is a matrix with an equal number of rows and columns, where all its elements are real numbers. Matrices can possess various special properties, and one such property defines them as skew-symmetric. Understanding these specific matrix properties is a fundamental aspect of matrix theory and linear algebra.
Before delving into the definition of a skew-symmetric matrix, let's first clarify the concept of a matrix transpose. The transpose of a matrix $A$, often denoted as $A^T$ (or $A'$), is formed by simply interchanging its rows and columns. If we consider a matrix $A$ where its elements are $a_{ij}$ (meaning the element in the $i$-th row and $j$-th column), then the corresponding element in its transpose $A^T$ will be $a_{ji}$.
For example, if we have a $2 \times 2$ matrix:
| $A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}$ |
Then its transpose $A^T$ would be:
| $A^T = \begin{pmatrix} a & c \\ b & d \end{pmatrix}$ |
A real square matrix $A$ is formally defined as skew-symmetric if its transpose is equal to the negative of the original matrix. This specific condition is mathematically represented as:
\(A^T = -A\)
This definition implies that for every element $a_{ij}$ located in the $i$-th row and $j$-th column of matrix $A$, the corresponding element $a_{ji}$ in the transpose $A^T$ must be equal to the negative of $a_{ij}$. Therefore, the relationship $a_{ji} = -a_{ij}$ must hold true for all possible values of $i$ and $j$.
An important implication of this matrix definition is that all the diagonal elements of a skew-symmetric matrix must be zero. This is because for diagonal elements, where $i = j$, the condition becomes $a_{ii} = -a_{ii}$. This equation simplifies to $2a_{ii} = 0$, which means $a_{ii} = 0$.
Consider an example of a $3 \times 3$ skew-symmetric matrix:
| $A = \begin{pmatrix} 0 & -2 & 3 \\ 2 & 0 & -1 \\ -3 & 1 & 0 \end{pmatrix}$ |
Let's compute its transpose $A^T$:
| $A^T = \begin{pmatrix} 0 & 2 & -3 \\ -2 & 0 & 1 \\ 3 & -1 & 0 \end{pmatrix}$ |
Now, let's calculate the negative of matrix $A$, which is $-A$:
| $-A = \begin{pmatrix} -(0) & -(-2) & -(3) \\ -(2) & -(0) & -(-1) \\ -(-3) & -(1) & -(0) \end{pmatrix} = \begin{pmatrix} 0 & 2 & -3 \\ -2 & 0 & 1 \\ 3 & -1 & 0 \end{pmatrix}$ |
As illustrated by this example, $A^T = -A$, which verifies that this matrix $A$ is indeed a skew-symmetric matrix.
Let's evaluate each of the provided options in the context of standard matrix properties and definitions:
Based on the established definitions of various matrix types and their characteristic properties, a real square matrix $A$ is officially classified as skew-symmetric if and only if its transpose is equivalent to the negative of the matrix itself, which is formally written as \(A^T = -A\).
Consider the system of equations: x + y = 2 and 2x + 2y = 5. This system has
The standard ordered basis of R 3 is {e 1, e 2, e 3} Let T : R 3 → R 3 be the linear transformation such that T(e 1) = 7e 1- 5e 3, T (e 2) = -2e 2+ 9e 3, T(e 3) = e 1+ e 2+ e 3. The standard matrix of T is:
The system of equations
x + y + z = 6;
x + 4y + 6z = 20;
x + 4y + λz = μ
has NO solution for values of λ and μ given by
What is the transformation matrix M that transforms a square in the xy-plane defined by (1, 1) T, (-1, 1) T, (-1, -1) T and (1, -1) T to a parallelogram whose corresponding vertices are (2, 1) T, (0, 1) T, (-2, -1) T and (0, -1) T?