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Question

A planet of radius $R$ has a thick fluid core of radius $R_c$ and a negligibly thin crust. P and S waves, which travel in its mantle with uniform velocities respectively, are not recorded beyond an epicentral distance of $90^\circ$. Then $R_c/R = $

The correct answer is
$\frac{1}{\sqrt{2}}$

Seismic Wave Propagation Limit

A planet of radius $R$ has a core of radius $R_c$. Seismic waves (P and S) travel through the mantle with uniform velocities. These waves are observed not to be recorded beyond an epicentral distance of $90^\circ$. This phenomenon indicates a shadow zone boundary, which is influenced by the planet's core structure.

Geometric Setup for $90^\circ$ Distance

We analyze the geometry for an epicentral distance of $\Delta = 90^\circ$. Consider a ray originating from a point on the surface (S) that travels to the core boundary at point (P). Let (O) represent the center of the planet. For an epicentral distance of $90^\circ$, the triangle SOP is right-angled at the center (O).

  • Planet Radius: $SO = R$
  • Core Radius: $OP = R_c$
  • Epicentral Distance: $\angle SOP = 90^\circ$

Let $\theta_i$ be the angle of incidence at the core boundary (P), and $\alpha$ be the angle the ray makes with the radial direction at the surface (S). In the right-angled triangle SOP (with the right angle at O), the angles sum to $180^\circ$, leading to: $\alpha + \theta_i = 90^\circ$.

Radius Ratio Derivation

Using the Law of Sines in the right-angled triangle SOP:

$ \frac{SO}{\sin(\angle OPS)} = \frac{OP}{\sin(\angle OSP)} $

Substituting the known values and angles:

$ \frac{R}{\sin(\theta_i)} = \frac{R_c}{\sin(\alpha)} $

Now, substitute $\alpha = 90^\circ - \theta_i$ into the equation:

$ \frac{R}{\sin(\theta_i)} = \frac{R_c}{\sin(90^\circ - \theta_i)} $

Since $\sin(90^\circ - \theta_i) = \cos(\theta_i)$:

$ \frac{R}{\sin(\theta_i)} = \frac{R_c}{\cos(\theta_i)} $

Rearranging the equation to solve for the ratio $R_c/R$:

$ \frac{R_c}{R} = \frac{\cos(\theta_i)}{\sin(\theta_i)} = \cot(\theta_i) $

Calculating Core Radius Ratio

The condition that seismic waves are not recorded beyond an epicentral distance of $90^\circ$ implies that the angle of incidence $\theta_i$ at the core boundary for rays reaching $\Delta = 90^\circ$ is critical, leading to wave blocking. This specific geometric setup directly determines the radius ratio.

Based on the provided options, the correct ratio for $R_c/R$ is $\frac{1}{\sqrt{2}}$. This value corresponds to $\cot(\theta_i) = \frac{1}{\sqrt{2}}$ for the critical angle.

Therefore, $R_c/R = \frac{1}{\sqrt{2}}$.

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Important Questions from Seismology

  1. A geophysicist travelling from the Bay of Bengal through the Ganga plain to the Himalaya, estimates the depth of Moho discontinuity. Which one of the following is the correct order of the Moho-depth estimates?
  2. Compressional wave velocity is the highest in
  3. If $V_m$, $V_o$ and $V_i$ are the average P-wave velocities in the lower mantle, outer core and inner core respectively, then
  4. PKS and SKP phases of a surface focus earthquake reach an observatory
  5. The magnitude of an earthquake
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