P’s salary is 20% lower than Q’s salary which is 20% lower than R’s salary. By how much
percent is R’s salary more than P’s salary?
56.25%
This question asks us to compare the salaries of three people, P, Q, and R, based on given percentage relationships. We are told that P's salary is 20% lower than Q's, and Q's salary is 20% lower than R's. We need to find out by what percentage R's salary is more than P's salary.
Let's use variables to represent the salaries:
Now we need to find the relationship between P's salary (\(S_P\)) and R's salary (\(S_R\)). We can substitute the expression for \(S_Q\) into the equation for \(S_P\):
\(S_P = 0.80 \times S_Q\)
Since \(S_Q = 0.80 \times S_R\), we have:
\(S_P = 0.80 \times (0.80 \times S_R)\)
\(S_P = (0.80 \times 0.80) \times S_R\)
\(S_P = 0.64 \times S_R\)
This tells us that P's salary is 0.64 times, or 64%, of R's salary.
The question asks by how much percent R's salary is more than P's salary. To find this, we calculate the difference between R's salary and P's salary, and then express this difference as a percentage of P's salary.
Difference in salary: \(S_R - S_P\)
We know \(S_P = 0.64 \times S_R\), so the difference is:
\(S_R - 0.64 \times S_R = (1 - 0.64) \times S_R = 0.36 \times S_R\)
The percentage increase of R's salary compared to P's salary is calculated as:
\(\text{Percentage Increase} = \frac{\text{Difference}}{\text{P's Salary}} \times 100\%\)
\(\text{Percentage Increase} = \frac{S_R - S_P}{S_P} \times 100\%\)
Substitute the expressions in terms of \(S_R\):
\(\text{Percentage Increase} = \frac{0.36 \times S_R}{0.64 \times S_R} \times 100\%\)
The \(S_R\) terms cancel out:
\(\text{Percentage Increase} = \frac{0.36}{0.64} \times 100\%\)
To simplify the fraction \(\frac{0.36}{0.64}\), we can write it as \(\frac{36}{64}\). Both numbers are divisible by 4:
\(\frac{36 \div 4}{64 \div 4} = \frac{9}{16}\)
Now, we convert this fraction to a percentage:
\(\frac{9}{16} \times 100\%\)
We can perform the division and multiplication:
\(9 \div 16 = 0.5625\)
\(0.5625 \times 100\% = 56.25\%\)
So, R's salary is 56.25% more than P's salary.
Let's check our calculated percentage increase against the given options:
| Option | Percentage |
|---|---|
| 1 | 48.75% |
| 2 | 60.50% |
| 3 | 62.25% |
| 4 | 56.25% |
Our calculated value, 56.25%, matches Option 4.
| Concept | Description | Formula Example |
|---|---|---|
| Percentage Decrease | Reducing a quantity by a percentage. If a quantity is decreased by x%, the new quantity is (100-x)% of the original. | New Value = Original Value \(\times (1 - \frac{x}{100})\) |
| Percentage Increase | Increasing a quantity by a percentage. If a quantity is increased by x%, the new quantity is (100+x)% of the original. | New Value = Original Value \(\times (1 + \frac{x}{100})\) |
| Finding Percentage Difference | Calculating how much one quantity is more or less than another, expressed as a percentage of the base quantity. | Percentage Difference = \(\frac{| \text{Value}_1 - \text{Value}_2 |}{\text{Base Value}} \times 100\%\) |
When solving percentage word problems, it's important to correctly identify the base value for the percentage calculation. In this problem, the initial decrease for P's salary is based on Q's salary, and the decrease for Q's salary is based on R's salary. However, the final question asks for the percentage increase of R's salary *more than* P's salary, which means the base for the final percentage calculation is P's salary.
A common mistake is to assume that consecutive percentage decreases (or increases) can be simply added or subtracted. A 20% decrease followed by another 20% decrease does not result in a 40% decrease overall from the original amount. Each percentage change is applied to the new, current value.
In this case, Q's salary is 80% of R's, and P's salary is 80% of Q's. So, P's salary is 80% of (80% of R's salary), which is \(0.80 \times 0.80 = 0.64\) or 64% of R's salary. The percentage increase from P to R is then calculated relative to P's salary.
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