A person borrowed some money on simple interest. After 3 years, he returned 4/3 of the money to the lender. What was the rate of interest?
To find the rate of interest, we can use the formula for Simple Interest ($SI$):
$$SI = \frac{P \times R \times T}{100}$$
Where:
$P$ = Principal (the money borrowed)
$R$ = Rate of interest per annum
$T$ = Time period in years
Step 1: Determine the Simple Interest
Let the principal amount borrowed be $P$.
After $3$ years ($T = 3$), the total amount ($A$) returned to the lender is $\frac{4}{3}$ of the borrowed money:
$$A = \frac{4}{3}P$$
The Simple Interest is the difference between the total amount returned and the principal:
$$SI = A - P$$
$$SI = \frac{4}{3}P - P = \frac{1}{3}P$$
Step 2: Substitute the values into the formula
Now, substitute $SI = \frac{1}{3}P$ and $T = 3$ into the simple interest formula:
$$\frac{1}{3}P = \frac{P \times R \times 3}{100}$$
Step 3: Solve for $R$
Since $P$ is on both sides, we can divide both sides by $P$:
$$\frac{1}{3} = \frac{3R}{100}$$
Cross-multiply to solve for $R$:
$$3 \times 3R = 100$$
$$9R = 100$$
$$R = \frac{100}{9}$$
$$R = 11\frac{1}{9}\% \text{ or approximately } 11.11\%$$
The rate of interest was $11\frac{1}{9}\%$ (or $11.11\%$ per annum).
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