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Question

A person borrowed some money on simple interest. After 3 years, he returned 4/3 of the money to the lender. What was the rate of interest?

The correct answer is
\(11\frac{1}{9}\) % p.a

To find the rate of interest, we can use the formula for Simple Interest ($SI$):

$$SI = \frac{P \times R \times T}{100}$$

Where:

$P$ = Principal (the money borrowed)

$R$ = Rate of interest per annum

$T$ = Time period in years

Step 1: Determine the Simple Interest

Let the principal amount borrowed be $P$.

After $3$ years ($T = 3$), the total amount ($A$) returned to the lender is $\frac{4}{3}$ of the borrowed money:

$$A = \frac{4}{3}P$$

The Simple Interest is the difference between the total amount returned and the principal:

$$SI = A - P$$

$$SI = \frac{4}{3}P - P = \frac{1}{3}P$$

Step 2: Substitute the values into the formula

Now, substitute $SI = \frac{1}{3}P$ and $T = 3$ into the simple interest formula:

$$\frac{1}{3}P = \frac{P \times R \times 3}{100}$$

Step 3: Solve for $R$

Since $P$ is on both sides, we can divide both sides by $P$:

$$\frac{1}{3} = \frac{3R}{100}$$

Cross-multiply to solve for $R$:

$$3 \times 3R = 100$$

$$9R = 100$$

$$R = \frac{100}{9}$$

$$R = 11\frac{1}{9}\% \text{ or approximately } 11.11\%$$

The rate of interest was $11\frac{1}{9}\%$ (or $11.11\%$ per annum).

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Important Questions from Simple Interest

  1. If ₹12,800 is invested in a bank for 5 years at the rate of 9% per annum simple interest. what amount is returned by the bank?

  2. Somu has borrowed ₹10,000 from a money lender with simple interest at a rate of 7% half yearly. How much amount will he pay to the money lender after 3 years?

  3. Find the Simple interest on Rs. 2,400 from 20 March 2019 to 31 may 2019 at \(6{1 \over 4}\) % rate?

  4. If the simple interest for five years is equal is 35% of the principal, that rate of interest is:

  5. A sum fetched a simple interest of Rs. 3,040 at the rate of 8% p.a in 5 years. what is the sum?

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