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Question

A number is increased by 10% and then decreased by 10%. It is again increased by 10%. What is the net increase or decrease per cent?

The correct answer is

8.9% increase 

Calculating Net Percentage Change After Sequential Modifications

This problem involves tracking the net effect of multiple percentage changes applied consecutively to an initial number.

Let's assume we start with an arbitrary number, say 100, to make the calculations easier to follow. We will apply the given percentage changes step-by-step.

Step 1: First Percentage Increase

The number is initially increased by 10%.

  • Starting number = 100
  • Increase amount = 10% of 100 = $\frac{10}{100} \times 100 = 10$
  • Number after the first increase = $100 + 10 = 110$

Step 2: Percentage Decrease

The result from Step 1 (110) is then decreased by 10%.

  • Number before decrease = 110
  • Decrease amount = 10% of 110 = $\frac{10}{100} \times 110 = 11$
  • Number after the decrease = $110 - 11 = 99$

Step 3: Second Percentage Increase

The result from Step 2 (99) is again increased by 10%.

  • Number before increase = 99
  • Increase amount = 10% of 99 = $\frac{10}{100} \times 99 = 9.9$
  • Final number = $99 + 9.9 = 108.9$

Calculating the Net Change

Now, we compare the final number (108.9) with the original number (100) to find the net change.

  • Original number = 100
  • Final number = 108.9
  • Net change = Final number - Original number = $108.9 - 100 = 8.9$

Since the final number (108.9) is greater than the original number (100), the net change is an increase.

Determining the Net Percentage Change

To find the net percentage change, we use the formula:

Net Percentage Change = $\frac{\text{Net Change}}{\text{Original Number}} \times 100\% $

Plugging in the values:

Net Percentage Change = $\frac{8.9}{100} \times 100\% = 8.9\%$

Therefore, there is a net increase of 8.9%.

Alternative Method Using Multipliers

We can also solve this using successive percentage multipliers.

  • A 10% increase corresponds to a multiplier of $(1 + \frac{10}{100}) = 1.1$.
  • A 10% decrease corresponds to a multiplier of $(1 - \frac{10}{100}) = 0.9$.

Applying these multipliers sequentially:

Final Value = Original Value $\times (1.1) \times (0.9) \times (1.1)$

Final Value = Original Value $\times (1.1 \times 0.9 \times 1.1)$

Final Value = Original Value $\times (0.99 \times 1.1)$

Final Value = Original Value $\times 1.089$

The net multiplier is 1.089.

To find the net percentage change:

Net Percentage Change = (Net Multiplier - 1) $\times 100\%$

Net Percentage Change = $(1.089 - 1) \times 100\% = 0.089 \times 100\% = 8.9\%$

Since the net multiplier (1.089) is greater than 1, this represents a net increase of 8.9%.

Conclusion on Net Change

Both methods confirm that after the sequence of a 10% increase, a 10% decrease, and another 10% increase, the net result is an 8.9% increase.

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Important Questions from Percentage (Notes)

  1. 20% of a number is more than 20% of 620 by 210. The number is:
  2. Girish scored 572 marks in an examination and was 30 marks short of 28% of maximum marks. In the same examination, his friend scored 473 marks. What is the percentage of marks scored by his friend?
  3. Anubhav spent 14% of his income on electricity bills, 28% on rent and 18% on shopping. If $\frac{1}{4}$ th of the remaining amount is ₹5120, how much did he spend on electricity bills ?
  4. The total population of a town is 50,000. The number of males and females increases by 10% and 15% respectively and consequently the population of the town becomes 56,000. What was the number of males in the town?
  5. There is an increase of 30% in the number of people coming to a theatre after reducing the entry fee by 25% per person. How much change is expected in the total earnings?
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