A molecular compound contains atoms A and B, where their counts per molecule are the 5th and 7th prime numbers from starting, respectively. The compound consists of 10 identical molecules. After a reaction, the number of B atoms per molecule doubles, and C atoms (equal to the 3rd prime number from starting) are added. What is the total number of A, B, and C atoms in all 10 molecules after the reaction?
500
The primes from the start are 2, 3, 5, 7, 11, 13, 17, … . So the 5th prime is 11 (A atoms per molecule), the 7th prime is 17 (B atoms per molecule) and the 3rd prime is 5 (C atoms added per molecule).
After the reaction, B atoms per molecule = 2 × 17 = 34. Atoms per molecule = 11 (A) + 34 (B) + 5 (C) = 50.
For 10 molecules the total is 10 × 50 = 500 atoms.
Hence, the answer is 500.
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