A is thrice as good a workman as B and is, therefore, able to finish a job in 60 days less than B. Working together, they can do it in:
22 1⁄2 days
Let B take x days to complete the job alone. Since A is thrice as efficient as B, A will take x - 60 days to complete the job.
Thus, A’s work per day = 1⁄x-60 and B’s work per day = 1⁄x.
Since A is thrice as efficient as B, we set up the equation:
1⁄x-60 = 3 × 1⁄x
Solving for x, we get x = 90, so B takes 90 days and A takes 30 days.
Work done by A and B together in 1 day:
1⁄30 + 1⁄90 = 4⁄90 = 2⁄45
Thus, time taken to complete the job together:
45 ⁄ 2 = 22 1⁄2 days.
Important Questions from Time and work
In a circular race on a track of length 2000 m, X and Y start from the same point at the same time in opposite directions at the speeds of 15 km/h and 33 km/h, respectively. After how much time will they meet next?
Which of the following option figures will complete the pattern in the figure given below?
A has completed two-third of a job in 8 days, and B completes the rest of the job in 20 days. In how many days can they together complete the job?
The smallest 4-digit prime number is:
If Anand can do a piece of work in 9 days and Vinod can complete the same work in 6 days, then in how many days will both of them complete it together?
