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Question

A is only $40\%$ as efficient as B. C is $50\%$ as efficient as A and B together. If C alone completes the task in $30\text{ days}$, then A, B and C together can complete the task in:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$10\text{ days}$

Understanding Efficiency Ratios

Let the efficiency of B be represented by $E_B$.

  • The efficiency of A ($E_A$) is $40\%$ of B's efficiency: $E_A = 0.40 \times E_B = 0.4 E_B$
  • The combined efficiency of A and B is: $E_A + E_B = 0.4 E_B + E_B = 1.4 E_B$
  • The efficiency of C ($E_C$) is $50\%$ of the combined efficiency of A and B: $E_C = 0.50 \times (E_A + E_B) = 0.5 \times (1.4 E_B) = 0.7 E_B$

Calculating Total Work and Combined Efficiency

Let the total work required to complete the task be $W$. The formula relating work, efficiency, and time is $W = \text{Efficiency} \times \text{Time}$.

  • We know C completes the task alone in $30$ days. Using C's efficiency: $W = E_C \times 30 \text{ days}$ $W = (0.7 E_B) \times 30 = 21 E_B$
  • Now, let's find the combined efficiency of A, B, and C working together: $E_{A+B+C} = E_A + E_B + E_C$ $E_{A+B+C} = 0.4 E_B + E_B + 0.7 E_B = 2.1 E_B$

Determining Time for Combined Effort

We need to find the time ($T$) it takes for A, B, and C together to complete the work $W$.

  • Using the formula $W = E_{A+B+C} \times T$: $21 E_B = (2.1 E_B) \times T$
  • Solve for $T$: $T = \frac{21 E_B}{2.1 E_B}$ $T = \frac{21}{2.1} = 10$

Therefore, A, B, and C together can complete the task in $10$ days.

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Important Questions from Time and Work

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