This problem involves calculating the time taken by a combined group based on individual work rates.
We are given that 15 men can reap a field in 22 days, and 25 women can reap the same field in 22 days. This means the total amount of work done by 15 men is equivalent to the work done by 25 women in the same amount of time.
Let $M$ be the work rate of one man (field per day) and $W$ be the work rate of one woman (field per day).
Total work = Rate $\times$ Time
Work done by 15 men in 22 days = $15 \times M \times 22$
Work done by 25 women in 22 days = $25 \times W \times 22$
Since the work is the same:
$15 \times M \times 22 = 25 \times W \times 22$
Simplifying this equation:
$15 M = 25 W$
$3 M = 5 W$
This establishes the relationship between the work rate of men and women: $M = \frac{5}{3} W$. One man's work rate is equivalent to $\frac{5}{3}$ women's work rate.
We need to find the time taken by 9 men and 18 women.
First, convert the work of 9 men into the equivalent work of women:
$9 \text{ men} = 9 \times M = 9 \times \left( \frac{5}{3} W \right) = 15 W$
Now, find the total equivalent number of women:
Total equivalent women = Work of 9 men (in women's units) + Work of 18 women
Total equivalent women = $15 W + 18 W = 33 W$
So, the combined group of 9 men and 18 women works at the same rate as 33 women.
We know that 25 women can reap the field in 22 days.
Total work required (in woman-days) = $25 \text{ women} \times 22 \text{ days} = 550 \text{ woman-days}$
Let $D$ be the number of days required for 33 women (equivalent to 9 men and 18 women) to reap the field.
Total work = Rate $\times$ Time
$550 \text{ woman-days} = 33 \text{ women} \times D \text{ days}$
Solve for $D$:
$D = \frac{550}{33}$
Divide both numerator and denominator by 11:
$D = \frac{50}{3}$
Convert the improper fraction to a mixed number:
$D = 16 \frac{2}{3} \text{ days}$
Therefore, 9 men and 18 women will take $16 \frac{2}{3}$ days to reap the field.
A and B can do a piece of work in 18 days. B and C together can do it in 30 days. If A is twice as good a workman as C, find in how many days B alone can do the work?
Two men and 7 women can complete a work in 28 days, whereas 6 men and 16 women can do the same work in 11 days. In how many days will 5 men and 4 women, working together, complete the same work?
A man and a woman, working together can do a work in 66 days. The ratio of their working efficiencies is 3 ∶ 2. In how many days 6 men and 2 women together can do the same work?
Each one of five men independently can complete a work in 20 days. The work is started by one person. Next day one more person joins and every next day one more person joins. From the fifth day, five persons continued working as a team. In how many days, will the work be completed?
Numan does half the work as Gagan in 4/5 of the time. If together they take 16 days to complete a piece of work, then how long will it take Gagan to complete the work?