A galvanometer may be converted into ammeter or voltmeter. In which of the following cases the resistance of the device will be the largest?
a voltmeter of range 10 V
A galvanometer is a sensitive instrument used to detect small electric currents. It can be modified to function as either an ammeter (to measure current) or a voltmeter (to measure voltage). The resistance of the resulting instrument depends heavily on how the conversion is done and the desired measurement range.
To convert a galvanometer into an ammeter, a low-resistance wire, called a shunt resistor ($R_s$), is connected in parallel with the galvanometer coil. This allows most of the current to bypass the galvanometer, protecting it and enabling the measurement of larger currents.
The total resistance ($R_A$) of the ammeter is the equivalent resistance of the parallel combination of the galvanometer resistance ($R_g$) and the shunt resistance ($R_s$): $$ R_A = \frac{R_g \times R_s}{R_g + R_s} $$ Since $R_s$ is chosen to be very small, the total resistance $R_A$ is also very small, typically much less than $R_g$. A higher current range (e.g., 10 A compared to 5 A) requires a larger shunt resistance ($R_s$), but the overall ammeter resistance ($R_A$) remains very low.
To convert a galvanometer into a voltmeter, a high-resistance wire, called a multiplier resistor ($R_m$), is connected in series with the galvanometer coil. This increases the total resistance, ensuring that only a small current flows through the galvanometer when a potential difference is applied, thereby measuring voltage accurately without significantly loading the circuit.
The total resistance ($R_V$) of the voltmeter is the sum of the galvanometer resistance ($R_g$) and the multiplier resistance ($R_m$): $$ R_V = R_g + R_m $$ The multiplier resistance $R_m$ is determined by the desired voltage range ($V$) and the galvanometer's current sensitivity ($I_g$). The relationship is $V = I_g (R_g + R_m)$. Thus, $R_m = \frac{V}{I_g} - R_g$. To measure a larger voltage range (e.g., 10 V compared to 5 V), a larger multiplier resistance ($R_m$) is needed. Consequently, the total voltmeter resistance ($R_V$) increases with the voltage range.
Based on the conversion methods:
Comparing the given options:
Therefore, the voltmeter with a range of 10 V will have the largest resistance.
The device with the largest resistance is the voltmeter designed to measure the highest voltage range, as it necessitates the inclusion of a high-value series resistor (multiplier).
A moving coil meter has a resistance of 100 Ω and at 5 V it gives full scale deflection. Find the value of external resistance to be connected in series for measuring 300 V.
Which of the following is correct for ammeter?
An instrument with an internal resistance of 100 Ω and a full-scale current of 1 mA is to be converted into a DC voltmeter with range of 0 V - 500 V. Find the value of the resistance used as a multiplier.
Considering extending the range of measuring instruments, the ratio \(\rm \frac{resistance \ of \ ammeter \ shunt }{resistance \ of \ voltmeter \ multiplier}=?\)
A 1 mA, 100 Ω meter movement is converted to a 100 mA ammeter using a parallel shunt resistor. If this shunt resistor suddenly becomes open-circuited while a steady line current of 80 mA is passing through the meter, what is the most likely outcome?