This problem requires calculating the cost per tonne for a foundry based on its fixed and variable production costs.
The total cost of production consists of two parts:
We need to find the total cost when the daily production ($Q$) is 100 tonnes.
VC = Rs $800 \times Q$
VC = Rs $800 \times 100 = \text{Rs } 80,000$
TC = FC + VC
TC = \text{Rs } 50,000 + \text{Rs } 80,000 = \text{Rs } 130,000$
The cost per tonne is calculated by dividing the Total Cost (TC) by the total production ($Q$).
Cost per Tonne = \frac{TC}{Q}
Cost per Tonne = \frac{\text{Rs } 130,000}{100 \text{ tonnes}} = \text{Rs } 1300 \text{ per tonne}
The calculated cost of production is Rs 1300 per tonne for a daily production of 100 tonnes. This value falls within the provided range.
Three frictionless pulleys with rope attachment are in a static equilibrium as shown in the figure. The mass $m_1$ and $m_2$, in kg, respectively are

If the in-situ density of coal is 1320 kg/m$^3$ and the density of blasted coal is 952 kg/m$^3$, the swell factor is _____________ (rounded off to 3 decimal places)
A five-member truss system is shown in the figure. The maximum vertical force P in kN that can be applied so that loads on the member CD and BC do NOT exceed 50 kN and 30 kN, respectively is _____________(rounded off to 2 decimal places)
The Fourier transform and its inverse transform are respectively defined as $\tilde{f}(\omega) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} f(x)e^{i\omega x}dx$ and $f(x) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} \tilde{f}(\omega)e^{-i\omega x}d\omega$. Consider two functions $f$ and $g$. Another function $f * g$ is defined as
$(f * g)(x) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} f(y)g(x - y)dy$
Which of the following relation is/are true?
Note: Tilde ($\sim$) denotes the Fourier transform.