This problem requires calculating the cost per tonne for a foundry based on its fixed and variable production costs.
The total cost of production consists of two parts:
We need to find the total cost when the daily production ($Q$) is 100 tonnes.
VC = Rs $800 \times Q$
VC = Rs $800 \times 100 = \text{Rs } 80,000$
TC = FC + VC
TC = \text{Rs } 50,000 + \text{Rs } 80,000 = \text{Rs } 130,000$
The cost per tonne is calculated by dividing the Total Cost (TC) by the total production ($Q$).
Cost per Tonne = \frac{TC}{Q}
Cost per Tonne = \frac{\text{Rs } 130,000}{100 \text{ tonnes}} = \text{Rs } 1300 \text{ per tonne}
The calculated cost of production is Rs 1300 per tonne for a daily production of 100 tonnes. This value falls within the provided range.
In an engineering college of 10,000 students, 1,500 like neither their core branches nor other branches. The number of students who like their core branches is 1/4th of the number of students who like other branches. The number of students who like both their core and other branches is 500.
The number of students who like their core branches is
$A$ is an ($n \times n$) matrix. Consider the following two statements
Statement 1: Columns of matrix $A$ are linearly independent
Statement 2: Inverse of matrix $A$ exists
Which one of the following statements is TRUE?