A dining - set listed at Rs. 5000 is sold to a man at successive discounts of 20% and 10% by the shopkeeper. What is the selling price of the dining set?
Rs. 3600
This problem involves calculating the final selling price of an item after two successive discounts are applied to its original listed price. Successive discounts mean that the second discount is calculated on the price after the first discount has been applied, not on the original listed price.
We need to apply the two successive discounts of 20% and 10% to the listed price of Rs. 5000.
The first discount is 20% on the listed price of Rs. 5000.
Discount Amount 1 = 20% of Rs. 5000
Discount Amount 1 $= \frac{20}{100} \times 5000$
Discount Amount 1 $= 0.20 \times 5000$
Discount Amount 1 $= 1000$
Price after First Discount = Listed Price - Discount Amount 1
Price after First Discount $= 5000 - 1000$
Price after First Discount $= 4000$
So, after the first 20% discount, the price of the dining set is Rs. 4000.
The second discount is 10%. This discount is applied to the price *after* the first discount, which is Rs. 4000.
Discount Amount 2 = 10% of Rs. 4000
Discount Amount 2 $= \frac{10}{100} \times 4000$
Discount Amount 2 $= 0.10 \times 4000$
Discount Amount 2 $= 400$
Selling Price = Price after First Discount - Discount Amount 2
Selling Price $= 4000 - 400$
Selling Price $= 3600$
Thus, after applying both successive discounts, the final selling price of the dining set is Rs. 3600.
When a discount of d% is given, the selling price is $(100-d)\%$ of the price. For successive discounts, we can multiply the remaining percentages.
So, the final selling price will be $90\%$ of $80\%$ of the original listed price.
Selling Price $= 90\%$ of $(80\%$ of $5000)$
Selling Price $= \frac{90}{100} \times (\frac{80}{100} \times 5000)$
Selling Price $= 0.90 \times (0.80 \times 5000)$
Selling Price $= 0.90 \times 4000$
Selling Price $= 3600$
Both methods yield the same result, confirming the selling price is Rs. 3600.
| Description | Amount (Rs.) | Calculation |
|---|---|---|
| Listed Price | 5000 | Given |
| First Discount (20%) | 1000 | 20% of 5000 |
| Price after 1st Discount | 4000 | 5000 - 1000 |
| Second Discount (10%) | 400 | 10% of 4000 |
| Final Selling Price | 3600 | 4000 - 400 |
The selling price of the dining set after successive discounts of 20% and 10% is Rs. 3600.
| Concept | Formula/Method | Example Application |
|---|---|---|
| Single Discount Amount | Discount % of Marked Price | 20% of 5000 = 1000 |
| Price after Single Discount | Marked Price - Discount Amount OR Marked Price $\times (1 - \frac{\text{Discount %}}{100})$ | 5000 - 1000 = 4000 OR $5000 \times (1 - \frac{20}{100}) = 5000 \times 0.8 = 4000$ |
| Price after Successive Discounts ($d_1\%$ and $d_2\%$) | Marked Price $\times (1 - \frac{d_1}{100}) \times (1 - \frac{d_2}{100})$ | $5000 \times (1 - \frac{20}{100}) \times (1 - \frac{10}{100}) = 5000 \times 0.8 \times 0.9 = 3600$ |
Instead of applying successive discounts one by one, we can calculate a single equivalent discount that would result in the same final selling price. If the successive discounts are $d_1\%$ and $d_2\%$, the single equivalent discount ($D\%$) is calculated as:
$D = d_1 + d_2 - \frac{d_1 \times d_2}{100}$
In this problem, $d_1 = 20\%$ and $d_2 = 10\%$.
Equivalent Single Discount $= 20 + 10 - \frac{20 \times 10}{100}$
Equivalent Single Discount $= 30 - \frac{200}{100}$
Equivalent Single Discount $= 30 - 2$
Equivalent Single Discount $= 28\%$
This means that successive discounts of 20% and 10% are equivalent to a single discount of 28% on the original marked price. Let's verify this:
Selling Price = Marked Price - 28% of Marked Price
Selling Price $= 5000 - \frac{28}{100} \times 5000$
Selling Price $= 5000 - 0.28 \times 5000$
Selling Price $= 5000 - 1400$
Selling Price $= 3600$
The selling price calculated using the equivalent single discount is also Rs. 3600, confirming the method.
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