Some fruits are bought at 15 for Rs. 140 and an equal number of fruits at 10 for Rs. 120. If all the fruits are sold at Rs. 132 per dozen, then what is the profit percent in the entire transaction?
This problem involves calculating the overall profit percentage when buying fruits from two different sources at different rates and selling them at a single rate. We need to determine the total cost price (CP) and the total selling price (SP) for a specific number of fruits to find the profit and subsequently the profit percent.
Fruits are bought from two different lots:
Let's find the cost of one fruit from each lot:
The problem states that an "equal number" of fruits are bought from both lots. To simplify calculations, we can choose a number of fruits that is a multiple of the quantities given in the buying rates (15 and 10). The least common multiple (LCM) of 15 and 10 is 30. Let's assume 30 fruits are bought from Lot 1 and 30 fruits are bought from Lot 2.
We assumed 30 fruits from each lot, making a total of \(30 + 30 = 60\) fruits.
Total Cost Price (CP) for 60 fruits = Cost from Lot 1 + Cost from Lot 2
Total CP = \(280 + 360 = 640\) Rupees.
All the fruits (60 fruits in total) are sold at Rs. 132 per dozen.
First, find out how many dozens are there in 60 fruits:
Number of dozens = \(\frac{\text{Total number of fruits}}{\text{Number of fruits in a dozen}} = \frac{60}{12} = 5\) dozens.
Now, calculate the total selling price:
Total Selling Price (SP) for 60 fruits = Number of dozens \(\times\) Selling price per dozen
Total SP = \(5 \times 132 = 660\) Rupees.
Profit is the difference between the Total Selling Price and the Total Cost Price.
Profit = Total SP - Total CP
Profit = \(660 - 640 = 20\) Rupees.
The profit percent is calculated using the formula:
\(\text{Profit Percent} = \left( \frac{\text{Profit}}{\text{Total CP}} \right) \times 100\)
Profit Percent = \(\left( \frac{20}{640} \right) \times 100\)
Simplify the fraction \(\frac{20}{640}\):
\(\frac{20}{640} = \frac{2}{64} = \frac{1}{32}\)
Now, calculate the percentage:
\(\text{Profit Percent} = \frac{1}{32} \times 100 = \frac{100}{32}\)
Simplify the fraction \(\frac{100}{32}\) by dividing both numerator and denominator by their greatest common divisor, which is 4:
\(\frac{100 \div 4}{32 \div 4} = \frac{25}{8}\)
Convert the improper fraction \(\frac{25}{8}\) into a mixed fraction:
\(25 \div 8 = 3\) with a remainder of \(1\).
So, \(\frac{25}{8} = 3 \frac{1}{8}\).
The profit percent in the entire transaction is \(3 \frac{1}{8}\).
| Item | Quantity | Rate | Total Cost |
|---|---|---|---|
| Fruits (Lot 1) | 15 | Rs. 140 | - |
| Fruits (Lot 2) | 10 | Rs. 120 | - |
| Assumed Quantity (Each Lot) | 30 | - | - |
| Cost of 30 from Lot 1 | 30 | @ \(\frac{140}{15}\)/fruit | Rs. 280 |
| Cost of 30 from Lot 2 | 30 | @ Rs. 12/fruit | Rs. 360 |
| Total Fruits Bought | 60 | - | - |
| Total Cost Price (CP) | 60 | - | Rs. 640 |
| Selling Rate | 1 dozen (12 fruits) | Rs. 132 | - |
| Total Fruits Sold | 60 | (= 5 dozen) | - |
| Total Selling Price (SP) | 60 | @ Rs. 132/dozen | Rs. 660 |
| Profit | - | - | Rs. 20 |
| Profit Percent | - | - | \(3 \frac{1}{8}\)% |
| Concept | Definition | Formula |
|---|---|---|
| Cost Price (CP) | The price at which an article is bought. | - |
| Selling Price (SP) | The price at which an article is sold. | - |
| Profit | When SP > CP. | Profit = SP - CP |
| Loss | When SP < CP. | Loss = CP - SP |
| Profit Percent | Profit expressed as a percentage of the Cost Price. | \(\left( \frac{\text{Profit}}{\text{CP}} \right) \times 100\) |
| Loss Percent | Loss expressed as a percentage of the Cost Price. | \(\left( \frac{\text{Loss}}{\text{CP}} \right) \times 100\) |
When solving profit and loss problems involving different purchase rates and a single selling rate, especially when equal quantities are involved, it's helpful to:
Using the LCM helps ensure we deal with whole numbers or simpler fractions for total costs, making the calculations smoother.
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