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Question

A catchment has eight raingauge stations. In a year, the annual rainfall recorded by the gauges (in cm) are 93.8, 106.5, 170.6, 138.7, 87.8, 156.2, 180.9 and 110.3. For a 10% error in the estimation of the mean rainfall, the optimum number of stations in the catchment is

The correct answer is
8

Calculating Optimum Number of Raingauge Stations

This analysis determines the minimum number of raingauge stations needed to estimate the mean annual rainfall accurately within a 10% error margin, using data from existing stations.

Input Data Summary

  • Number of existing stations: $N = 8$
  • Annual rainfall (cm): 93.8, 106.5, 170.6, 138.7, 87.8, 156.2, 180.9, 110.3
  • Allowable percentage error: $p = 10\% = 0.10$

Step 1: Calculate Mean Rainfall

Compute the average rainfall from the existing stations.

$ \bar{x} = \frac{93.8 + 106.5 + 170.6 + 138.7 + 87.8 + 156.2 + 180.9 + 110.3}{8} $

The mean rainfall is:

$ \bar{x} = \frac{944.8}{8} = 118.1 \text{ cm} $

Step 2: Calculate Standard Deviation

Determine the standard deviation ($\sigma$) of the rainfall data to understand its variability. Using the sample standard deviation formula:

$ \sigma = \sqrt{\frac{\sum_{i=1}^{N}(x_i - \bar{x})^2}{N-1}} $

First, calculate the sum of squared differences from the mean:

$ \sum_{i=1}^{8}(x_i - 118.1)^2 \approx 10280 $

Calculate the variance ($\sigma^2$):

$ \sigma^2 = \frac{10280}{8-1} = \frac{10280}{7} \approx 1468.57 $

Calculate the standard deviation ($\sigma$):

$ \sigma = \sqrt{1468.57} \approx 38.32 \text{ cm} $

Step 3: Determine Optimum Number of Stations

Use the formula to find the minimum number of stations ($n_{opt}$) required for the desired error tolerance ($p$):

$ n_{opt} = \left( \frac{\sigma}{\bar{x} p} \right)^2 $

Substitute the values:

$ n_{opt} = \left( \frac{38.32}{118.1 \times 0.10} \right)^2 $

Calculate the value:

$ n_{opt} = \left( \frac{38.32}{11.81} \right)^2 \approx (3.245)^2 \approx 10.53 $

Since the number of stations must be a whole number, round up:

$ n_{opt} = \lceil 10.53 \rceil = 11 $

Result Interpretation

The calculation indicates that 11 raingauge stations are needed for a 10% error tolerance. Based on this calculation, the existing 8 stations are insufficient.

Note: The calculated value (11) is not among the provided options (4, 6, 8, 10). The standard method yields 11 stations required.

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Important Questions from Precipitation Analysis

  1. By depth-area-duration analysis, the maximum average depth of rainfall over a $10^3\text{ km}^2$ catchment due to a 6-hour storm is $80\text{ mm}$. For the same storm, the maximum average depth of rainfall for a $10^4\text{ km}^2$ catchment, in mm, is
  2. In a basin, rainfall is recorded by five automatic weather stations A, B, C, D and E with respective average annual rainfall of 1020, 810, 675, 940 and 780 mm. In a particular year, the station A was non-operational and the remaining stations B, C, D and E recorded annual rainfall of 890, 725, 980 and 850 mm, respectively. The estimated rainfall at the station A in that particular year in mm is
  3. A soil conservation structure has an expected life of 10 years and is designed for a flood magnitude of return period 50 years. The risk of this hydrologic design in percentage (rounded off to two decimal places) is ____________.

  4. The normal annual rainfall for 5 rain guage stations A, B, C, D and E in a watershed were 112.7, 120.4, 118.3, 125.2 and 110.6 cm, respectively. In a particular year, the rain gauge installed at station C failed to record rainfall. In the same year the rain gauges at stations A, B, D and E recorded annual rainfall of 114.9, 118.3, 122.6 and 114.5 cm, respectively. The estimated rainfall at station C in that particular year in cm was __________
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