A car has an initial velocity of 12 m/s and is brought to rest over a distance of 45 m. The acceleration of the car is
-0.8 m/s²
Correct Answer: (d) -0.8 m/s²
Explanation: Using the equation of motion v² = u² + 2as, where v = 0, u = 12 m/s, and s = 45 m, we find the acceleration as -0.8 m/s².
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