A can do a work in 30 days and B can do the same work in 40 days. They work together for 8 days and then B leaves the work. In how many days will A finish the remaining work?
16
- A's 1-day work = 1/30, B's 1-day work = 1/40.
- Together, in 1 day, they complete:
(1/30) + (1/40) = (4/120) + (3/120) = 7/120.
- In 8 days, they complete:
8 × (7/120) = 56/120 = 14/30.
- Remaining work = 1 - 14/30 = 16/30.
- A alone will complete this in (16/30) × 30 = 16 days.
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