All Exams Test series for 1 year @ ₹349 only
Question

A bipolar junction common emitter transistor is operating in saturation mode, identify the correct statement.

The correct answer is

Vce is zero

Bipolar Junction Transistor Operating Modes

A bipolar junction transistor (BJT) is a three-terminal semiconductor device used for amplification or switching applications. It has three main operating regions: cut-off, active, and saturation. Each region is defined by the biasing conditions of its two internal junctions: the emitter-base junction and the collector-base junction.

  • Cut-off Region: In this region, both the emitter-base and collector-base junctions are reverse-biased. The transistor acts like an open switch, and there is virtually no collector current (\(I_c\)).
  • Active Region: This is the region where the transistor functions as an amplifier. The emitter-base junction is forward-biased, and the collector-base junction is reverse-biased. The collector current (\(I_c\)) is proportional to the base current (\(I_b\)).
  • Saturation Region: In this region, both the emitter-base and collector-base junctions are forward-biased. The transistor acts like a closed switch, and the collector current (\(I_c\)) reaches its maximum possible value, limited by the external circuit components rather than the base current.

Saturation Mode of a Common Emitter Transistor

When a common emitter bipolar junction transistor operates in saturation mode, it behaves much like a closed switch. This means that the collector current (\(I_c\)) is at its maximum possible value, determined primarily by the collector resistor (\(R_c\)) and the supply voltage (\(V_{cc}\)).

In saturation mode, the transistor is said to be "fully ON". For silicon transistors, the emitter-base junction is forward-biased, leading to a typical base-emitter voltage (\(V_{be}\)) of around \(0.7\,V\). Crucially, the collector-emitter voltage (\(V_{ce}\)) drops to a very small value, often referred to as \(V_{ce(sat)}\).

The \(V_{ce(sat)}\) value for a typical silicon transistor is usually in the range of \(0.1\,V\) to \(0.3\,V\). While not exactly zero, for many simplified analyses and multiple-choice questions, it is approximated as being very close to zero because it represents the lowest possible voltage drop across the collector-emitter terminals when the transistor is conducting maximum current.

Analyzing Transistor Statements in Saturation

Let's evaluate each given statement concerning a bipolar junction common emitter transistor operating in saturation mode:

  • 1. Vce is zero

    In saturation mode, the collector-emitter voltage (\(V_{ce}\)) is at its minimum value, typically \(V_{ce(sat)}\) (around \(0.1\,V\) to \(0.3\,V\)). While not precisely zero, it is often approximated as zero in ideal models or as the "closest to zero" option among choices, indicating that the transistor acts as a closed switch with minimal voltage drop. Given the options, this statement is considered the most accurate representation of \(V_{ce}\) in saturation.

  • 2. Vbe is zero

    For a silicon common emitter transistor to be in saturation mode, its base-emitter junction must be forward-biased. This means that the base-emitter voltage (\(V_{be}\)) will be approximately \(0.7\,V\) (for silicon). Therefore, \(V_{be}\) is definitely not zero in saturation mode.

  • 3. Ic is zero

    In saturation mode, the collector current (\(I_c\)) is at its maximum possible value, determined by the external circuitry (\(I_{c(sat)} \approx \frac{V_{cc} - V_{ce(sat)}}{R_c}\)). The current is limited only by the load resistance and supply voltage. If \(I_c\) were zero, the transistor would be in the cut-off region, not saturation mode.

  • 4. Vcc = Vce

    This condition typically occurs when the transistor is in the cut-off region, meaning \(I_c = 0\). If \(I_c = 0\), then the voltage drop across the collector resistor (\(I_c \times R_c\)) is zero, and thus \(V_{ce} = V_{cc}\). In saturation mode, \(V_{ce}\) is very small and much less than \(V_{cc}\) (e.g., \(0.1\,V\) to \(0.3\,V\)), so this statement is incorrect for saturation mode.

Based on the analysis, the statement that best describes a bipolar junction common emitter transistor operating in saturation mode, especially in the context of multiple-choice questions where ideal approximations are common, is that \(V_{ce}\) is very low, approaching zero.

Summary of BJT Operating Regions

The table below summarizes the key characteristics of a Bipolar Junction Transistor (BJT) in its different operating regions:


Operating Region Emitter-Base Junction Collector-Base Junction Collector Current (\(I_c\)) Collector-Emitter Voltage (\(V_{ce}\)) Transistor Behavior
Cut-off Reverse-biased Reverse-biased Approximately zero (\(\approx 0\)) Approximately \(V_{cc}\) (\(\approx V_{cc}\)) Open switch (OFF)
Active Forward-biased Reverse-biased \(I_c = \beta I_b\) (proportional to \(I_b\)) Between \(V_{ce(sat)}\) and \(V_{cc}\) Amplifier
Saturation Forward-biased Forward-biased Maximum (\(I_{c(sat)}\)) Approximately \(V_{ce(sat)}\) (\(\approx 0.1\,V - 0.3\,V\)) Closed switch (ON)

Therefore, for a bipolar junction common emitter transistor in saturation mode, \(V_{ce}\) is indeed very close to zero, making "Vce is zero" the most appropriate correct statement among the given options.

Was this answer helpful?

Important Questions from Bipolar Junction Transistor

  1. Photo transistor is used for:

  2. What happens if a voltage of about 0.7 V is applied across the base and emitter of the NPN transistor?

  3. In a junction transistor, recombination of electrons and holes occurs in

  4. In BJT when both the junctions are forward biased, then its operating mode is called:

  5. When a bipolar junction transistor is operating in the saturation mode, which one of the following statements is TRUE about the state of its collector-base (CB) and the base-emitter (BE) junctions?

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App