A baseball is moving at 25 m/s. When it is struck by a bat moves off in the opposite direction at 35 m/s. If the impact lasted 0.010 s, find the baseball's acceleration during the impact.
-6000 m/s 2
Let's break down this physics problem about baseball acceleration during impact. We are given the initial velocity of a baseball, its final velocity after being hit by a bat, and the duration of the impact. Our goal is to find the acceleration of the baseball during this short time.
First, we need to be careful about the direction of velocity. Velocity is a vector quantity, meaning it has both magnitude and direction. Let's assume the initial direction of the baseball is positive.
The time duration of the impact is given as $\Delta t = 0.010$ s. This short impact time leads to a significant velocity change.
The change in velocity ($\Delta \vec{v}$) is the difference between the final velocity and the initial velocity:
$$\Delta \vec{v} = \vec{v}_{final} - \vec{v}_{initial}$$
Plugging in the values:
$$\Delta \vec{v} = (-35 \text{ m/s}) - (25 \text{ m/s})$$
$$\Delta \vec{v} = -35 \text{ m/s} - 25 \text{ m/s}$$
$$\Delta \vec{v} = -60 \text{ m/s}$$
The negative sign indicates that the overall change in velocity is in the direction opposite to the initial motion. This large velocity change occurs over a very short impact time.
Acceleration ($\vec{a}$) is defined as the rate of change of velocity. It is calculated by dividing the change in velocity by the time interval over which the change occurs:
$$\vec{a} = \frac{\Delta \vec{v}}{\Delta t}$$
Using the values we found:
$$\vec{a} = \frac{-60 \text{ m/s}}{0.010 \text{ s}}$$
To perform this calculation, divide -60 by 0.010:
$$\vec{a} = -6000 \text{ m/s}^2$$
The acceleration of the baseball during the impact is $-6000 \text{ m/s}^2$. The negative sign indicates that the acceleration is in the direction opposite to the initial velocity, which makes sense because the bat reverses the baseball's motion. This high value is typical for the acceleration during impact in sports like baseball.
This type of physics problem involving motion and forces is common in introductory physics. Understanding how to handle velocity change and impact time is key to solving such problems related to baseball acceleration.
Therefore, the baseball's acceleration during the impact is $-6000 \text{ m/s}^2$. This calculation helps us understand the forces involved in changing the baseball's motion so drastically in a short impact time.
Acceleration is equal to the rate of change of _________.
At uniform speed the acceleration is
At uniform speed the acceleration is