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Question

Which of the following mathematical expressions accurately defines the average acceleration, $a$, of an object that changes its velocity from an initial velocity $v_i$ to a final velocity $v_f$ during a time interval $t$?

The correct answer is
$a = (v_f - v_i) / t$

Defining Average Acceleration ($a$)

In physics, acceleration describes how an object's velocity changes over time. Velocity includes both speed and direction. When an object's velocity is not constant, it is accelerating.

The average acceleration ($a$) is calculated over a specific period. It represents the total change in velocity divided by the total time taken for that change to occur. This gives us a measure of the acceleration averaged over the entire time interval, smoothing out any variations within that interval.

Mathematical Expression for Average Acceleration

To define the average acceleration, we consider:

  • The initial velocity ($v_i$): The velocity of the object at the beginning of the time interval.
  • The final velocity ($v_f$): The velocity of the object at the end of the time interval.
  • The time interval ($t$): The duration over which the velocity changes.

The change in velocity is calculated as the final velocity minus the initial velocity:

$ \Delta v = v_f - v_i $

The average acceleration ($a$) is then found by dividing this change in velocity ($\Delta v$) by the time interval ($t$):

$ a = \frac{\Delta v}{t} $

Substituting the expression for $\Delta v$, we get the formula:

$ a = \frac{v_f - v_i}{t} $

Analyzing the Options for Average Acceleration

Let's examine each provided option based on the definition of average acceleration:

  • Option 1: $a = (v_f + v_i) / t$

    This expression incorrectly adds the initial and final velocities instead of finding the difference. The change in velocity is required, not the sum.

  • Option 2: $a = (v_f - v_i) \cdot t$

    This option multiplies the change in velocity by the time interval. Average acceleration is defined as the change in velocity *divided* by the time interval, not multiplied.

  • Option 3: $a = \Delta x / t^2$

    This expression involves displacement ($\Delta x$) and time squared ($t^2$). While related to motion, this formula does not represent the definition of average acceleration, which specifically relates to the change in velocity over time.

  • Option 4: $a = (v_f - v_i) / t$

    This expression correctly represents the change in velocity ($v_f - v_i$) divided by the time interval ($t$). This aligns perfectly with the definition of average acceleration.

  • Option 5: (Empty Option)

    This option is not provided.

Conclusion on Average Acceleration Formula

The definition of average acceleration ($a$) is the rate at which velocity changes over a specific time interval ($t$). It is calculated by taking the difference between the final velocity ($v_f$) and the initial velocity ($v_i$), and then dividing the result by the time interval.

Therefore, the correct mathematical expression is:

$ a = \frac{v_f - v_i}{t} $

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Important Questions from Acceleration

  1. Acceleration is equal to the rate of change of _________.

  2. At uniform speed the acceleration is

  3. At uniform speed the acceleration is

  4. If the position of a particle X at time $t$ is given by the equation $x(t) = At^3$, where $A$ is a non-zero constant, determine the nature of its acceleration.
  5. A particle moves a distance $x$ in time $t$ according to the equation $x = (2t+3)^{-1/2}$. The acceleration of the particle is proportional to

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