A ball is moving with a constant speed in a circular path in a vertical plane. The system is illuminated from the top so that the shadow of the ball on the ground oscillates. The maximum probability of finding the shadow of the ball is at
The problem describes a ball moving with constant speed in a circular path in a vertical plane. The system is illuminated from the top, casting a shadow of the ball on the ground. We need to determine where the probability of finding this shadow is maximum.
When an object moves in a circle and is illuminated by parallel light rays perpendicular to the plane of motion, its shadow on a screen perpendicular to the light rays executes Simple Harmonic Motion (SHM).
In this case, the ball moves in a vertical circular path, and the illumination is from the top. This means the light rays are essentially vertical, perpendicular to the horizontal ground. The shadow on the ground is the projection of the ball's position onto the ground. As the ball moves around the vertical circle, its horizontal position (on the ground) will oscillate back and forth along a straight line segment. This oscillatory motion of the shadow is Simple Harmonic Motion.
In Simple Harmonic Motion, the speed of the oscillating object is not constant. The speed is maximum at the mean position (center of oscillation) and minimum (zero) at the extreme positions (the points where the object reverses direction).
The probability of finding the object at a particular point is related to how long the object spends in the vicinity of that point. The longer the object spends near a point, the higher the probability of finding it there.
Since the shadow, undergoing SHM, spends the most time near the extreme points of its oscillation, the probability of finding the shadow is maximum at these extreme points.
Based on the properties of Simple Harmonic Motion, the shadow spends the most time at its turning points, which are the extreme points of the oscillation. Therefore, the probability of finding the shadow is highest at the extreme points.
In an examination 10,000 students appeared. The result revealed the number of students who have:
passed in all five subjects = 5583
passed in three subjects only = 1400
passed in two subjects only = 1200
passed in one subject only = 735
failed in English only = 75
failed in Physics only = 145
failed in Chemistry only = 140
failed in Mathematics only = 200
failed in Bio-science only = 157
The number of students passed in at least four subjects is:
How many hollow spheres having inner radius of 1 cm can be completely filled by transferring water from a completely filled hollow sphere having inner diameter of 20 cm ?
The period of a pendulum is given as T = 2 π (l/g)1/2 where g = 9.81 m/s2 and π = 3.1416. The period of a pendulum of length 1 m correct to the first place of decimal in seconds is