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Question

How many hollow spheres having inner radius of 1 cm can be completely filled by transferring water from a completely filled hollow sphere having inner diameter of 20 cm ?

The correct answer is

1000

Understanding the Problem

The question asks us to determine how many small hollow spheres can be completely filled with water from a single large hollow sphere that is completely filled. This involves comparing the volumes of the spheres. The total volume of water available is the volume of the large sphere. This volume will be distributed among the smaller spheres.

Sphere Volume Calculation

The volume of a sphere is given by the formula:

\( V = \frac{4}{3}\pi r^3 \)

where \( V \) is the volume and \( r \) is the radius of the sphere.

Identifying Sphere Dimensions

  • The small hollow spheres have an inner radius of 1 cm. Let \( r_s \) be the radius of a small sphere. So, \( r_s = 1 \text{ cm} \).
  • The large hollow sphere has an inner diameter of 20 cm. Let \( D_L \) be the diameter of the large sphere. So, \( D_L = 20 \text{ cm} \).

The radius of the large sphere, \( R_L \), is half of its diameter:

\( R_L = \frac{D_L}{2} = \frac{20 \text{ cm}}{2} = 10 \text{ cm} \)

Calculating Sphere Volumes

Let's calculate the volume of one small sphere, \( V_s \), using its radius \( r_s = 1 \text{ cm} \):

\( V_s = \frac{4}{3}\pi (r_s)^3 = \frac{4}{3}\pi (1)^3 = \frac{4}{3}\pi \times 1 = \frac{4}{3}\pi \text{ cm}^3 \)

Now, let's calculate the volume of the large sphere, \( V_L \), using its radius \( R_L = 10 \text{ cm} \):

\( V_L = \frac{4}{3}\pi (R_L)^3 = \frac{4}{3}\pi (10)^3 = \frac{4}{3}\pi \times 1000 \text{ cm}^3 \)

Determining the Number of Spheres

The total volume of water from the large sphere is \( V_L \). If this water is used to fill \( N \) small spheres, the total volume of water in these small spheres will be \( N \times V_s \). Since all the water from the large sphere is used to fill the small spheres, we have:

\( V_L = N \times V_s \)

Substitute the calculated volumes:

\( \frac{4}{3}\pi \times 1000 = N \times \frac{4}{3}\pi \)

To find \( N \), we can divide both sides of the equation by \( \frac{4}{3}\pi \):

\( N = \frac{\frac{4}{3}\pi \times 1000}{\frac{4}{3}\pi} \)

\( N = 1000 \)

Therefore, 1000 hollow spheres having an inner radius of 1 cm can be completely filled by transferring water from a completely filled hollow sphere having an inner diameter of 20 cm.

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Important Questions from Numerical Ability

  1. Arrange in the correct sequence the Percentage method of recipe adjustment.

    (i) Determine the total weight of the product needed.
    (ii) Calculate the percentage of each ingredient in relation to total weight.
    (iii) Convert all ingredients in recipe to gram unit and determine edible portion.
    (iv) Check the ratio of ingredients which should be in proper balance.
    (v) Multiply each percentage number by the total weight to give exact amount of the ingredient needed.
    (vi) Total the weight of ingredients using edible portion.

    Choose the correct answer from the code given below :
  2. In an examination 10,000 students appeared. The result revealed the number of students who have:

    passed in all five subjects = 5583

    passed in three subjects only = 1400

    passed in two subjects only = 1200

    passed in one subject only = 735

    failed in English only = 75

    failed in Physics only = 145

    failed in Chemistry only = 140

    failed in Mathematics only = 200

    failed in Bio-science only = 157

    The number of students passed in at least four subjects is:

  3. Four identical cones with base diameter of 10 cm are compactly placed inside a box in upright position. What will be the area of square (in cm2) formed by connecting tips of the cones?
  4. The period of a pendulum is given as T = 2 π (l/g)1/2 where g = 9.81 m/s2 and π = 3.1416. The period of a pendulum of length 1 m correct to the first place of decimal in seconds is

  5. The sides a, b and c of a Δ ABC satisfy the equation (a – 8)2 + (b - 15)2 + (c - 17)2 = 0. Then Δ ABC is

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