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Question

A 4 bit ripple counter and a 4 bit synchronous counter are made by flips flops having a propagation delay of 10 ns each. If the worst case delay in the ripple counter and the synchronous counter be R and S respectively, then

The correct answer is

R = 40 ns, S = 10 ns

This question asks us to compare the worst-case delay of a 4-bit ripple counter and a 4-bit synchronous counter, given that each flip-flop used has a propagation delay of 10 ns.

Ripple Counter Worst-Case Delay Calculation (R)

A ripple counter, also known as an asynchronous counter, connects flip-flops in a serial manner. The output of one flip-flop serves as the clock input for the next flip-flop. This sequential clocking means that the clock signal (or the change in output) effectively 'ripples' through the counter.

For a 4-bit ripple counter, there are 4 flip-flops. The total worst-case delay occurs when the last flip-flop changes its state based on the output change from the first flip-flop. This delay is the sum of the propagation delays of all the flip-flops in the chain.

  • Propagation delay per flip-flop = $10 \text{ ns}$
  • Number of flip-flops = 4

Therefore, the worst-case delay for the ripple counter (R) is calculated as:

$$ R = \text{Number of flip-flops} \times \text{Propagation delay per flip-flop} $$ $$ R = 4 \times 10 \text{ ns} $$ $$ R = 40 \text{ ns} $$

Synchronous Counter Worst-Case Delay Calculation (S)

In a synchronous counter, all flip-flops are triggered simultaneously by a common clock signal. The next state of each flip-flop is determined by the current state and the counter's logic (e.g., using AND gates to control the clock enable or J-K inputs).

Since all flip-flops receive the clock pulse at the same time, the delay associated with the clock triggering is the delay of a single flip-flop. The time it takes for the counter to transition to the next state is primarily limited by the time it takes for any single flip-flop to change its output after the clock edge arrives and its inputs are stable.

For a 4-bit synchronous counter, the worst-case delay (S) is determined by the propagation delay of a single flip-flop because all flip-flops change state almost simultaneously after the clock pulse.

  • Propagation delay per flip-flop = $10 \text{ ns}$

Therefore, the worst-case delay for the synchronous counter (S) is:

$$ S = \text{Propagation delay per flip-flop} $$ $$ S = 10 \text{ ns} $$

Conclusion

Based on the calculations:

  • Worst-case delay for the 4-bit ripple counter (R) = $40 \text{ ns}$
  • Worst-case delay for the 4-bit synchronous counter (S) = $10 \text{ ns}$

This corresponds to the option stating R = 40 ns and S = 10 ns.

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Important Questions from Digital Electronics

  1. Latches are _______ circuits.

  2. First generation computers had which of the following?

  3. The 8085 has two registers known as primary data pointers. These are registers

  4. Which of the following is a non-positional number system?

  5. The digital equivalent of an electric series circuit is the:

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