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Question

How many flip flops is/are required for 10 state count in ripple counter?

The correct answer is

Four

Ripple Counter Flip-Flop Requirements

A ripple counter, also known as an asynchronous counter, is a fundamental type of sequential circuit in digital electronics. In these counters, the output of one flip-flop acts as the clock input for the next flip-flop. This cascading arrangement allows the counter to increment its state based on the clock pulses, creating a "ripple" effect as the state changes propagate through the chain of flip-flops.

Counter State Capacity Explained

The total number of unique states (or count values) that a binary counter can represent is directly determined by the number of flip-flops it contains. Each flip-flop can store one binary digit (0 or 1). If a counter is built using 'm' flip-flops, then each flip-flop contributes one bit to the overall binary representation of the count.

  • With 'm' flip-flops, there are 'm' bits available to represent the count.
  • The total number of distinct combinations that can be formed with 'm' bits is $2^m$.
  • Therefore, an 'm'-bit counter can count through $2^m$ unique states, ranging from 0 up to $2^m - 1$.

Calculating Flip-Flops for 10 States

To determine the minimum number of flip-flops required for a specific number of states, say 'N' states, we need to find the smallest integer 'm' such that the maximum counting capacity of 'm' flip-flops is greater than or equal to the required number of states. The formula for this relationship is:

$$\text{Number of states desired } (N) \le 2^m$$

In this particular question, we need a counter that can count 10 states. So, we set $N = 10$. We then need to find the smallest 'm' that satisfies $10 \le 2^m$. Let's test values for 'm':

  • If we use $m = 1$ flip-flop, the maximum states are $2^1 = 2$. This is not enough to count 10 states.
  • If we use $m = 2$ flip-flops, the maximum states are $2^2 = 4$. This is not enough to count 10 states.
  • If we use $m = 3$ flip-flops, the maximum states are $2^3 = 8$. This is not enough to count 10 states.
  • If we use $m = 4$ flip-flops, the maximum states are $2^4 = 16$. This is greater than or equal to 10 states.

Since $2^4 = 16$ is the first power of 2 that meets or exceeds the requirement of 10 states, a minimum of 4 flip-flops are needed.

Ripple Counter Design Consideration

For a 10-state ripple counter (often called a Mod-10 counter), the counter needs to be able to represent binary values from 0000 (0) up to 1001 (9). A 4-bit counter (using 4 flip-flops) naturally counts from 0000 to 1111 (0 to 15). To make it a 10-state counter, additional logic (like a NAND gate and a clear input) is typically used to reset all flip-flops to 0000 when the counter reaches the binary equivalent of 10 (which is 1010). Even with this reset mechanism, the underlying capacity to reach at least state 9 requires enough bits to represent it, which 4 bits provide.

Therefore, to count 10 states, Four flip-flops are required.

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Important Questions from Digital Electronics

  1. Which of the following is a non-positional number system?

  2. Radix 2 is used for representing

  3. First generation computers had which of the following?

  4. Which of the following logic gate gives high output with all its inputs low

  5. Latches are _______ circuits.

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