All Exams Test series for 1 year @ ₹349 only
Question

How many flip flops is/are required for 10 state count in ripple counter?

The correct answer is

Four

Ripple Counter Flip-Flop Requirements

A ripple counter, also known as an asynchronous counter, is a fundamental type of sequential circuit in digital electronics. In these counters, the output of one flip-flop acts as the clock input for the next flip-flop. This cascading arrangement allows the counter to increment its state based on the clock pulses, creating a "ripple" effect as the state changes propagate through the chain of flip-flops.

Counter State Capacity Explained

The total number of unique states (or count values) that a binary counter can represent is directly determined by the number of flip-flops it contains. Each flip-flop can store one binary digit (0 or 1). If a counter is built using 'm' flip-flops, then each flip-flop contributes one bit to the overall binary representation of the count.

  • With 'm' flip-flops, there are 'm' bits available to represent the count.
  • The total number of distinct combinations that can be formed with 'm' bits is $2^m$.
  • Therefore, an 'm'-bit counter can count through $2^m$ unique states, ranging from 0 up to $2^m - 1$.

Calculating Flip-Flops for 10 States

To determine the minimum number of flip-flops required for a specific number of states, say 'N' states, we need to find the smallest integer 'm' such that the maximum counting capacity of 'm' flip-flops is greater than or equal to the required number of states. The formula for this relationship is:

$$\text{Number of states desired } (N) \le 2^m$$

In this particular question, we need a counter that can count 10 states. So, we set $N = 10$. We then need to find the smallest 'm' that satisfies $10 \le 2^m$. Let's test values for 'm':

  • If we use $m = 1$ flip-flop, the maximum states are $2^1 = 2$. This is not enough to count 10 states.
  • If we use $m = 2$ flip-flops, the maximum states are $2^2 = 4$. This is not enough to count 10 states.
  • If we use $m = 3$ flip-flops, the maximum states are $2^3 = 8$. This is not enough to count 10 states.
  • If we use $m = 4$ flip-flops, the maximum states are $2^4 = 16$. This is greater than or equal to 10 states.

Since $2^4 = 16$ is the first power of 2 that meets or exceeds the requirement of 10 states, a minimum of 4 flip-flops are needed.

Ripple Counter Design Consideration

For a 10-state ripple counter (often called a Mod-10 counter), the counter needs to be able to represent binary values from 0000 (0) up to 1001 (9). A 4-bit counter (using 4 flip-flops) naturally counts from 0000 to 1111 (0 to 15). To make it a 10-state counter, additional logic (like a NAND gate and a clear input) is typically used to reset all flip-flops to 0000 when the counter reaches the binary equivalent of 10 (which is 1010). Even with this reset mechanism, the underlying capacity to reach at least state 9 requires enough bits to represent it, which 4 bits provide.

Therefore, to count 10 states, Four flip-flops are required.

Was this answer helpful?

Important Questions from Digital Electronics

  1. Latches are _______ circuits.

  2. First generation computers had which of the following?

  3. The 8085 has two registers known as primary data pointers. These are registers

  4. Which of the following is a non-positional number system?

  5. The digital equivalent of an electric series circuit is the:

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App