A 230 V lamp is rated to pass a current of 0.24 A. Calculate its power output. If a second similar lamp is connected in parallel to the lamp, calculate the supply current required to give the same power output in each lamp.
0.48 A
This problem involves calculating the power output of a single lamp and then determining the total supply current when two such lamps are connected in a parallel circuit.
To calculate the power output of a single lamp, we can use the fundamental formula that relates voltage, current, and power. The power (P) is the product of the voltage (V) across the component and the current (I) flowing through it. The question provides the voltage rating of the lamp and the current it passes.
The formula for power output is:
\( P = V \times I \)
Substituting the given values into the formula:
\( P = 230 \text{ V} \times 0.24 \text{ A} \)
\( P = 55.2 \text{ W} \)
Therefore, the power output of a single lamp is 55.2 Watts.
When a second similar lamp is connected in parallel to the first lamp, a few key principles of parallel circuits apply:
Let's denote the current through the first lamp as \(I_1\) and the current through the second lamp as \(I_2\).
The total supply current (\(I_{\text{total}}\)) is the sum of these individual currents:
\( I_{\text{total}} = I_1 + I_2 \)
Substituting the values:
\( I_{\text{total}} = 0.24 \text{ A} + 0.24 \text{ A} \)
\( I_{\text{total}} = 0.48 \text{ A} \)
Thus, the total supply current required to power two similar lamps connected in parallel, ensuring each lamp maintains its rated power output, is 0.48 A.
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