A 100 : 5 current transformer is used in conjunction with a 5 A ammeter. If the later reads 3.5 A, find the line current.
A current transformer (CT) is a device used in electrical power systems to measure high alternating currents safely. It works on the principle of electromagnetic induction to produce a reduced current in its secondary winding that is proportional to the current flowing in its primary winding. This reduced current can then be easily measured by standard instruments like an ammeter, which typically has a rating of 5 A.
In this problem, we are given:
The relationship between the primary current (line current), secondary current (ammeter reading), and the CT ratio can be expressed as:
$$ \text{CT Ratio} = \frac{\text{Primary Current}}{\text{Secondary Current}} $$
We can rearrange this formula to find the Primary Current (Line Current):
$$ \text{Primary Current} = \text{CT Ratio} \times \text{Secondary Current} $$
The CT ratio is given as 100:5, which can be written as a factor:
$$ \text{CT Factor} = \frac{100}{5} = 20 $$
The secondary current, as read by the ammeter, is 3.5 A.
$$ \text{Line Current} = \text{CT Factor} \times \text{Secondary Current} $$
$$ \text{Line Current} = 20 \times 3.5 \, \text{A} $$
$$ \text{Line Current} = 70 \, \text{A} $$
Therefore, the actual line current is 70 A.
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A potential transformer of 12000/112 V and current transformer of 80/6 A are used to measure voltage and current in a transmission line. If the voltmeter indicates 120 V and current reads 5 A, what is the voltage and current in this line?