-(-6) [3 - {8 - (-3)}] ÷ [4{12 + (-3) × 6}] = ?
2
Concept Used:
To solve this question, follow the BODMAS rule according to the order given below:
Given:
-(-6) [3 - {8 - (-3)}] ÷ [4{12 + (-3) × 6}] = ?
Calculation:
-(-6) [3 - {8 - (-3)}] ÷ [4{12 + (-3) × 6}] = ?
⇒ 6 [3 - {8 + 3}] ÷ [4{12 - 3 × 6}] = ?
⇒ 6 [3 - 11] ÷ [4{12 - 18}] = ?
⇒ 6 [- 8] ÷ [4 × {- 6}] = ?
⇒ - 48 ÷ [- 24] = ?
⇒ - 48/- 24 = ?
⇒ 48/24 = ?
⇒ 2 = ?
∴ The value of ? is 2.
Mistake Points
( + ) × ( - ) = -
( + ) × ( + ) = +
( - ) × ( + ) = -
Important Questions from Bodmas Rule
The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:
The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:
The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:
The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:
The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is:
