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Question

\( \sqrt{2{\cdot}25} + \sqrt{0{\cdot}0064} + \sqrt{2{\cdot}89} + 1 \) is equal to :

This question was previously asked in
UPSSSC PET 2026 Question Paper (01-Nov-2026) (Shift-1)
The correct answer is

4·28

\( \sqrt{2.25} = 1.5 \) since \( 1.5^{2} = 2.25 \)

\( \sqrt{0.0064} = 0.08 \) since \( 0.08^{2} = 0.0064 \); \( \sqrt{2.89} = 1.7 \) since \( 1.7^{2} = 2.89 \)

Sum = \( 1.5 + 0.08 + 1.7 + 1 = 4.28 \)

Check: \( 1.5 + 1.7 = 3.2 \), \( 3.2 + 0.08 + 1 = 4.28 \).

Tip: a perfect square decimal always has an even number of decimal places, and its root has half as many.

Hence, 4·28.

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