(1235)8 is equivalent to-
(029D)16
The question asks us to convert the octal number (1235)8 into its equivalent hexadecimal representation.
To convert an octal number to a hexadecimal number, a common method is to first convert the octal number to its binary equivalent, and then convert the binary number to its hexadecimal equivalent.
Each digit in an octal number (base 8) can be represented by exactly 3 binary digits (bits), since \(2^3 = 8\). We convert each octal digit of (1235)8 into its 3-bit binary equivalent:
Concatenating these binary representations, we get:
1 \(\rightarrow\) 001
2 \(\rightarrow\) 010
3 \(\rightarrow\) 011
5 \(\rightarrow\) 101
So, the binary equivalent of (1235)8 is 001010011101.
Each digit in a hexadecimal number (base 16) can be represented by exactly 4 binary digits (bits), since \(2^4 = 16\). To convert the binary number 001010011101 to hexadecimal, we group the binary digits in sets of 4, starting from the rightmost digit. If the leftmost group has fewer than 4 digits, we add leading zeros to complete the group.
Our binary number is 001010011101.
Grouping in sets of 4 from right to left:
1101
0011
0100
001
The leftmost group '001' has only 3 digits. We add a leading zero to make it 4 digits: '0001'. (Wait, let's re-check the grouping from the original binary 001010011101)
Let's group correctly from right:
Binary: 0010 1001 1101
Group 1 (rightmost): 1101
Group 2: 1001
Group 3 (leftmost): 0010
Now, we convert each 4-bit group into its hexadecimal equivalent:
Combining these hexadecimal digits from left to right (corresponding to the binary groups from left to right), we get 29D.
So, the hexadecimal equivalent of the binary number 001010011101 is (29D)16.
| Octal Digit | Binary (3-bit) |
|---|---|
| 1 | 001 |
| 2 | 010 |
| 3 | 011 |
| 5 | 101 |
| Binary (001010011101) | Grouped Binary (4-bit) | Decimal Value | Hexadecimal Digit |
|---|---|---|---|
| (Reading from left) | 0010 | 2 | 2 |
| 1001 | 9 | 9 | |
| 1101 | 13 | D |
Therefore, (1235)8 is equivalent to (29D)16.
Comparing this result with the given options, we see that option 1 is (029D)16. A leading zero does not change the value of a number, so (29D)16 is the same as (029D)16.
The conversion process yields (29D)16. Option 1 is (029D)16, which is the same value. Thus, option 1 is the correct equivalent.
| Conversion Type | Method | Example |
|---|---|---|
| Octal to Binary | Replace each octal digit with its 3-bit binary equivalent. | (47)8 = (100 111)2 |
| Binary to Octal | Group binary bits in threes from right, convert each group to octal digit. | (110101)2 = (110 101)2 = (65)8 |
| Binary to Hexadecimal | Group binary bits in fours from right, convert each group to hexadecimal digit. | (11011010)2 = (1101 1010)2 = (D A)16 |
| Hexadecimal to Binary | Replace each hexadecimal digit with its 4-bit binary equivalent. | (A3)16 = (1010 0011)2 |
| Octal to Hexadecimal | Convert Octal to Binary, then Binary to Hexadecimal. | (Steps explained above) |
| Hexadecimal to Octal | Convert Hexadecimal to Binary, then Binary to Octal. | (2A)16 = (0010 1010)2 = (001 010 100)2 = (124)8 |
Number systems use different bases to represent quantities. The base indicates the number of unique digits used in the system, including zero.
Understanding the relationship between bases, especially how bases 8 and 16 relate to base 2, simplifies conversions between these systems.
The number of digit 1 present in the binary representation of 3 × 512 + 5 × 64 + 7 × 8 + 3 is:
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How many bits are required to represent (1000) 10 in BCD code?
A code in which only one bit changes between successive numbers is known as ______ code.