The problem asks for the time it takes for two trains moving in opposite directions to completely pass each other.
The speeds are given in km/h, but the lengths are in meters and the required time is in seconds. We need to convert the speeds using the factor $\frac{5}{18}$.
When two objects move in opposite directions, their relative speed is the sum of their individual speeds.
Relative Speed ($S_{rel}$) = $S_1 + S_2$
$S_{rel} = \left( 149 \times \frac{5}{18} \right) + \left( 139 \times \frac{5}{18} \right) \text{ m/s}$ $S_{rel} = (149 + 139) \times \frac{5}{18} \text{ m/s}$ $S_{rel} = 288 \times \frac{5}{18} \text{ m/s}$ $S_{rel} = 16 \times 5 \text{ m/s}$ $S_{rel} = 80 \text{ m/s}$For the trains to pass each other completely, the total distance covered relative to each other is the sum of their lengths.
Length of Z1 Express ($L_1$) = 755 m
Length of X1 Express ($L_2$) = 685 m
Total Relative Distance ($D_{rel}$) = $L_1 + L_2$
$D_{rel} = 755 \text{ m} + 685 \text{ m}$ $D_{rel} = 1440 \text{ m}$The time taken is the total relative distance divided by the relative speed.
Time ($T$) = $\frac{D_{rel}}{S_{rel}}$
$T = \frac{1440 \text{ m}}{80 \text{ m/s}}$ $T = 18 \text{ seconds}$Train A leaves station M at 6:40 AM and reaches station N at 3:40 PM on the same day. Train B leaves station N at 8:40 AM and reaches station M at 2:40 PM on the same day. Find the time when trains A and B meet.