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Question

$x[n]$ is a real and odd signal. Which one of the following statements is true about its Discrete Time Fourier Transform (DTFT) $X(e^{j\omega})$?

The correct answer is
$X(e^{j\omega})$ is imaginary and odd

DTFT Properties for Real and Odd Signals

We need to determine the characteristics (real/imaginary, even/odd) of the Discrete Time Fourier Transform (DTFT), $X(e^{j\omega})$, for a signal $x[n]$ that is both real and odd.

Signal Properties and DTFT

Key properties relating a signal $x[n]$ and its DTFT $X(e^{j\omega})$ are:

  • If $x[n]$ is real, then $X(e^{j\omega}) = X^*(e^{-j\omega})$.
  • If $x[n]$ is odd, then $x[n] = -x[-n]$.

Deriving $X(e^{j\omega})$ Properties

Let's combine these properties:

  1. Real Signal Property: Since $x[n]$ is real, we have:

    $X(e^{j\omega}) = X^*(e^{-j\omega})$

  2. Odd Signal Property: For an odd signal, the DTFT satisfies $X(e^{-j\omega}) = -X(e^{j\omega})$.
  3. Combining Properties: Substitute the odd signal property into the real signal property:

    $X(e^{j\omega}) = (X(e^{-j\omega}))^* = (-X(e^{j\omega}))^*$

    Let $X(e^{j\omega}) = A + jB$, where $A$ is the real part and $B$ is the imaginary part.

    Then $X^*(e^{j\omega}) = A - jB$. The equation becomes:

    $A + jB = -(A - jB)$

    $A + jB = -A + jB$

    Equating the real parts gives $A = -A$, which implies $A = 0$.

    This means $X(e^{j\omega})$ has no real part, so it must be purely imaginary ($X(e^{j\omega}) = jB$).

  4. Odd Function Property: We already established from the odd signal property that $X(e^{-j\omega}) = -X(e^{j\omega})$. This is the definition of an odd function.

Conclusion

Combining the results, the DTFT $X(e^{j\omega})$ of a real and odd signal $x[n]$ is both purely imaginary and an odd function.

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Important Questions from Fourier Transform

  1. The FT of $x(t) = e^{4t} u(-t)$ is:
  2. The function f(t) is a periodic function of period 2π. In the range (-π, π), it equals e-t. If f(t) = \(\sum\nolimits_{ - \infty }^\infty {{c_n}{e^{{\mathop{\rm int}} }}}\) denotes its Fourier series expansion, the sum \({\sum\nolimits_{ - \infty }^\infty {\left| {{c_n}} \right|} ^2}\) is

  3. Fourier transform of the unit impulse δ(t) is

  4. Differentiating a signal in the time domain corresponds to _________ its FT in the frequency domain by _________.

  5. The function f(t) has a Fourier transform F(ω). The Fourier transform of F(t) is

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