We need to determine the characteristics (real/imaginary, even/odd) of the Discrete Time Fourier Transform (DTFT), $X(e^{j\omega})$, for a signal $x[n]$ that is both real and odd.
Key properties relating a signal $x[n]$ and its DTFT $X(e^{j\omega})$ are:
Let's combine these properties:
$X(e^{j\omega}) = X^*(e^{-j\omega})$
$X(e^{j\omega}) = (X(e^{-j\omega}))^* = (-X(e^{j\omega}))^*$
Let $X(e^{j\omega}) = A + jB$, where $A$ is the real part and $B$ is the imaginary part.
Then $X^*(e^{j\omega}) = A - jB$. The equation becomes:
$A + jB = -(A - jB)$
$A + jB = -A + jB$
Equating the real parts gives $A = -A$, which implies $A = 0$.
This means $X(e^{j\omega})$ has no real part, so it must be purely imaginary ($X(e^{j\omega}) = jB$).
Combining the results, the DTFT $X(e^{j\omega})$ of a real and odd signal $x[n]$ is both purely imaginary and an odd function.
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