$X^4 + C$ is the general integral of
The question asks to find the expression whose general integral is $X^4 + C$. We need to evaluate the given options to see which one results in this form.
First, evaluate the indefinite integral $\int x^3dx$. Using the power rule for integration, which states that $\int x^n dx = \frac{x^{n+1}}{n+1} + C$ (where $n \neq -1$), we get:
$ \int x^3dx = \frac{x^{3+1}}{3+1} + C_1 = \frac{x^4}{4} + C_1 $Here, $C_1$ represents the constant of integration.
Now, multiply the result by 4, as given in Option D:
$ 4 \times \left( \frac{x^4}{4} + C_1 \right) $Distribute the 4:
$ 4 \times \frac{x^4}{4} + 4 \times C_1 = x^4 + 4C_1 $Since $C_1$ is an arbitrary constant, $4C_1$ is also an arbitrary constant. Let $C = 4C_1$. The expression simplifies to:
$ x^4 + C $Assuming $X$ in the question refers to the variable $x$, this matches the general integral $X^4 + C$.
The expression $4\int x^3dx$ evaluates to the general integral $X^4 + C$. Therefore, Option D is the correct answer.
What is \(\rm \int \frac{dx}{x(x^2 + 1)}\) equal to?
If \(\rm \int \sqrt{1 - sin 2x} \space dx\) = A sinx + B cosx + C, where 0 < x < \(\frac{\pi}{4}\) , then which one of the following is correct?
What is \(\smallint {{\rm{e}}^{\sin {\rm{x}}}}\left( {\frac{{{\rm{x}}{{\cos }^3}{\rm{x}} - \sin {\rm{x}}}}{{{{\cos }^2}{\rm{x}}}}} \right){\rm{dx}}\) equal to?