Work done during a process can be determined by \(\smallint {\rm{pdv}}\) when the process is
Quasi-static
In thermodynamics, work done by a system is often represented on a pressure-volume (P-V) diagram. The amount of work done depends on the path taken by the process connecting the initial and final states.
The formula given, \(\smallint {\rm{pdv}}\), represents the work done by the system during a volume change from an initial volume \(V_1\) to a final volume \(V_2\), where p is the pressure of the system at any given volume V. This integral calculates the area under the process curve on a P-V diagram.
The fundamental requirement for the work done by a system to be accurately calculated using the formula \(\smallint {\rm{pdv}}\) is that the process must be a quasi-static process.
When a process is quasi-static, the pressure 'p' in the formula \(\smallint {\rm{pdv}}\) is the well-defined thermodynamic pressure of the system, which is exerted uniformly on the boundary that is moving (causing the volume change dv).
Let's look at the other options:
The formula \(\smallint {\rm{pdv}}\) specifically calculates the boundary work for a system undergoing a quasi-static expansion or compression. In non-quasi-static processes (like a rapid expansion or compression), the pressure within the system may not be uniform, and the work done at the boundary may not be equal to \(\smallint {\rm{pdv}}\) based on the internal system pressure. The integral \(\smallint {\rm{pdv}}\) correctly represents the work done by the system on its surroundings only when the process is quasi-static.
Therefore, the work done during a process can be determined by \(\smallint {\rm{pdv}}\) when the process is quasi-static.
Which of the following pairs of thermodynamic properties can uniquely fix the state of a substance like water, irrespective of its thermodynamic state?
A reversible polytropic process can be described by
The pressure inside a balloon is proportional to the square of its diameter. It contains 2 kg of water at 150 kPa with 85% quality. The balloon and water are now heated so that a final pressure of 600 kPa is reached. The process undergone by the water is given by p-v equation as:
A non-flow device compresses air isothermally at a temperature of 500°C from a pressure of 5 MPa to a final pressure of 15 MPa. If the device uses 200 kJ/kg of work input, then this process is:
Choose the INCORRECT option for the process and its work done (W) and heat transfer (Q) relations.