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Question

Read the following paragraph carefully and answer the following five questions:

In a ninth standard class of 50 students, the teacher administered test to measure achievement of students in Physics and Chemistry, respectively. The mean and SD of the class for the achievement scores in Physics were 50 and 20 , respectively whereas, the mean and SD of the class for the achievement scores in Chemistry were 20 and 5 respectively.

One student Rekha scored 30 marks in Physics and 26 marks in Chemistry. Another student Reshma scored 56 marks in Physics and 22.5 marks in Chemistry. Another student Sameer scored 46 marks in Physics and 19 marks in Chemistry. The summary of these scores is given below:

S ubject Mean of the class SD of the classRekha Reshma Sameer
Physics 50 20 30 56 46
Chemistry 20526 22.519

Who had the poorest score on either test?

The correct answer is Rekha

Understanding Student Performance Comparison

The question asks us to identify the student who had the poorest performance on either the Physics or the Chemistry test among Rekha, Reshma, and Sameer. We are given their scores, along with the mean and standard deviation for the entire class in each subject. Simply comparing the raw scores might be misleading because the tests likely have different difficulty levels and scoring scales, as indicated by the different means and standard deviations.

To compare performance across different tests or subjects, it is often useful to standardize the scores. A common way to do this is by calculating a Z-score for each student's score in each subject. The Z-score tells us how many standard deviations a student's score is above or below the mean of the class for that specific test.

The formula for calculating a Z-score ($$z$$) is:

$$z = \frac{x - \mu}{\sigma}$$

Where:

  • $$x$$ is the individual student's score.
  • $$\mu$$ is the mean score of the class for that test.
  • $$\sigma$$ is the standard deviation of the class scores for that test.

A lower (more negative) Z-score indicates a poorer performance relative to the class mean.

Calculating Z-Scores for Each Student

First, let's summarize the given data:

Subject Mean ($$\mu$$) SD ($$\sigma$$) Rekha's Score (x) Reshma's Score (x) Sameer's Score (x)
Physics 50 20 30 56 46
Chemistry 20 5 26 22.5 19

Now, let's calculate the Z-score for each student in each subject:

Rekha:

  • Physics Z-score: $$z_{Physics} = \frac{30 - 50}{20} = \frac{-20}{20} = -1.0$$
  • Chemistry Z-score: $$z_{Chemistry} = \frac{26 - 20}{5} = \frac{6}{5} = 1.2$$

Reshma:

  • Physics Z-score: $$z_{Physics} = \frac{56 - 50}{20} = \frac{6}{20} = 0.3$$
  • Chemistry Z-score: $$z_{Chemistry} = \frac{22.5 - 20}{5} = \frac{2.5}{5} = 0.5$$

Sameer:

  • Physics Z-score: $$z_{Physics} = \frac{46 - 50}{20} = \frac{-4}{20} = -0.2$$
  • Chemistry Z-score: $$z_{Chemistry} = \frac{19 - 20}{5} = \frac{-1}{5} = -0.2$$

Comparing Z-Scores to Determine Poorest Performance

Let's list the Z-scores for each student in each subject:

Student Physics Z-score Chemistry Z-score
Rekha -1.0 1.2
Reshma 0.3 0.5
Sameer -0.2 -0.2

We are looking for the student who had the poorest score on *either* test. In terms of relative performance (measured by Z-scores), a more negative Z-score indicates poorer performance. Let's look at the lowest Z-score for each student across their two tests:

  • Rekha's lowest Z-score: -1.0 (in Physics)
  • Reshma's lowest Z-score: 0.3 (in Physics)
  • Sameer's lowest Z-score: -0.2 (in both Physics and Chemistry)

Comparing these lowest Z-scores (-1.0, 0.3, -0.2), the lowest value is -1.0. This is Rekha's Z-score in Physics.

Therefore, based on the standardized scores (Z-scores), Rekha had the poorest performance relative to her class mean in Physics, and this relative performance is the lowest among the lowest relative performances of all three students in either test.

Although Sameer had the lowest raw score (19 in Chemistry), his performance relative to the Chemistry class (Z-score -0.2) was not as poor as Rekha's performance relative to the Physics class (Z-score -1.0).

Conclusion on Poorest Student Performance

By calculating and comparing the Z-scores, we can determine the student who performed worst relative to their class in either subject. Rekha's Z-score of -1.0 in Physics is the lowest among all calculated Z-scores, indicating her performance was 1 standard deviation below the mean in Physics, which is the poorest relative performance observed.

Revision Table: Key Concepts for Comparing Scores

Concept Description Relevance to Question
Raw Score The actual number of marks obtained on a test. Directly given, but hard to compare across different tests.
Mean ($$\mu$$) The average score of the class for a test. Point of reference for class performance.
Standard Deviation ($$\sigma$$) A measure of the spread or variability of scores around the mean. Indicates how typical or unusual a score is.
Z-score ($$z$$) A standardized score indicating how many standard deviations a raw score is from the mean. Allows comparison of scores from different distributions. A lower (more negative) Z-score means poorer relative performance.

Additional Information: Why Standardize Scores?

Comparing raw scores directly from different tests can be misleading because tests might have different maximum possible scores, different difficulty levels, and different distributions of scores. For example, scoring 60 on a test where the average is 70 is different from scoring 60 on a test where the average is 40. Standardizing scores, like calculating Z-scores, helps us understand a student's performance in the context of the group that took the test.

A Z-score tells us how far a particular score is from the mean, expressed in units of standard deviation. A positive Z-score means the score is above the mean, a negative Z-score means it's below the mean, and a Z-score of 0 means the score is exactly at the mean. The magnitude of the Z-score indicates how far the score is from the mean in standard deviation units. By using Z-scores, we can compare a student's relative standing in Physics to their relative standing in Chemistry, even though the tests have different scales and averages.

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Important Questions from Data Interpretation

  1. The table shows the monthly expenditure of Saumya. What percent of her monthly salary is she able to save?

    ExpenseAmount
    Food5,000
    Rent20,000
    Travel10,000
    Clothing3,000
    Miscellaneous15,000
    Savings7,500

  2. Who had the best score on either test?

  3. Who had the most consistent scores on both tests?

  4. Who had the least consistent scores on both tests?

  5. Who had the best mean score on both tests?

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