Which of the following statements is correct?
If A is triangular, A -1 is also triangular
Let's analyze the given statements about matrices to determine which one is correct. The question asks us to identify the correct property among the given options related to different types of matrices and matrix operations.
We will examine each statement one by one, discussing the relevant matrix properties and providing explanations or counterexamples where necessary. Understanding these properties is crucial for working with matrices.
A triangular matrix is a special type of square matrix where all elements either above or below the main diagonal are zero.
For a matrix to have an inverse (be invertible), its determinant must be non-zero. A well-known property in linear algebra states that if an invertible matrix A is upper triangular, its inverse A-1 is also upper triangular. Similarly, if A is a lower triangular matrix, its inverse A-1 is also lower triangular.
Consider a 2x2 upper triangular matrix:
\[ A = \begin{pmatrix} a & b \\ 0 & c \end{pmatrix} \]For A to be invertible, \( \det(A) = ac - b(0) = ac \neq 0 \). This means \( a \neq 0 \) and \( c \neq 0 \). The matrix inverse is given by:
\[ A^{-1} = \frac{1}{\det(A)} \begin{pmatrix} c & -b \\ 0 & a \end{pmatrix} = \frac{1}{ac} \begin{pmatrix} c & -b \\ 0 & a \end{pmatrix} = \begin{pmatrix} 1/a & -b/ac \\ 0 & 1/c \end{pmatrix} \]As we can see, A-1 is also an upper triangular matrix. A similar verification can be done for a lower triangular matrix. This statement is correct.
The adjoint of a matrix, denoted as adj(A), is the transpose of the cofactor matrix. Let's consider the adjoint matrix properties. A fundamental property relating the adjoint of the transpose is that for any square matrix A:
\[ \text{adj}(A^T) = (\text{adj}(A))^T \]This means the adjoint of the transpose is the transpose of the adjoint, not necessarily the adjoint itself unless A is a symmetric matrix (where \(A^T = A\)) AND its adjoint is also symmetric (which is not generally true for any symmetric matrix). For a general matrix A, adj(AT) is the transpose of adj(A). Therefore, this statement is incorrect.
This statement relates the adjoint of a product of matrices to the product of their adjoints. The property for the adjoint of a product of two square matrices A and B of the same order n is:
\[ \text{adj}(AB) = (\text{adj} B) (\text{adj} A) \]Note the reverse order of the adjoints on the right side. This is similar to the property for the inverse of a product, \( (AB)^{-1} = B^{-1} A^{-1} \). The given statement, adj (AB) = (adj A) (adj B), is incorrect due to the order of multiplication. This is another important matrix property.
Since we found that Statement 1 is correct, this statement claiming all options are incorrect must be false.
Based on our analysis of the matrix properties presented in each statement:
Therefore, the only correct statement among the given options is Statement 1.
What should be the value of x so that the matrix \(\left( {\begin{array}{*{20}{c}} 2&4\\ { - 8}&{\rm{x}} \end{array}} \right)\) does not have an inverse?
What is the adjoint of the matrix \(\left( {\begin{array}{*{20}{c}} {\cos \left( { - \theta } \right)}&{ - \sin \left( { - \theta } \right)}\\ { - \sin \left( { - \theta } \right)}&{\cos \left( { - \theta } \right)} \end{array}} \right)\) ?
The inverse of the matrix A = \(\left( {\begin{array}{} 1&1&3\\ 1&3&{ - 3}\\ { - 2}&{ - 4}&{ - 4} \end{array}} \right)\) is:
What is the inverse of the matrix?
\(A = \left( {\begin{array}{*{20}{c}} {\cos \theta }&{\sin \theta }&0\\ { - \sin \theta }&{\cos \theta }&0\\ 0&0&1 \end{array}} \right)\)
If A and B are two invertible square matrices of same order, then what is (AB) -1 equal to?