Which of the following set contains same number of molecules? A. 1 gram O 2, 2 grams SO 2 B. 1 gram CO 2, 1 gram N 2O C. 1 gram O 2, 1 gram O 3
A and B
The number of molecules in a given sample of a substance is directly related to the number of moles of that substance. One mole of any substance contains Avogadro's number (approximately $\text{6.022} \times \text{10}^{23}$) of molecules.
To find the number of moles from a given mass, we use the formula:
$\text{Moles} = \frac{\text{Mass (in grams)}}{\text{Molar Mass (in grams per mole)}}$
Therefore, to find which sets contain the same number of molecules, we need to calculate the number of moles for each substance in each set and compare them. If the number of moles is the same, the number of molecules will also be the same.
Let's determine the molar mass for each substance mentioned in the question:
Now, let's calculate the number of moles (and thus compare the number of molecules) for each set:
| Set | Substance | Mass | Molar Mass | Moles ($\frac{\text{Mass}}{\text{Molar Mass}}$) | Number of Molecules (proportional to moles) |
|---|---|---|---|---|---|
| A | $\text{O}_2$ | 1 gram | 32 g/mol | $\frac{1}{32}$ mol | $\frac{1}{32} \times N_A$ |
| A | $\text{SO}_2$ | 2 grams | 64 g/mol | $\frac{2}{64} = \frac{1}{32}$ mol | $\frac{1}{32} \times N_A$ |
| B | $\text{CO}_2$ | 1 gram | 44 g/mol | $\frac{1}{44}$ mol | $\frac{1}{44} \times N_A$ |
| B | $\text{N}_2\text{O}$ | 1 gram | 44 g/mol | $\frac{1}{44}$ mol | $\frac{1}{44} \times N_A$ |
| C | $\text{O}_2$ | 1 gram | 32 g/mol | $\frac{1}{32}$ mol | $\frac{1}{32} \times N_A$ |
| C | $\text{O}_3$ | 1 gram | 48 g/mol | $\frac{1}{48}$ mol | $\frac{1}{48} \times N_A$ |
Let's look at the results:
Based on the calculations, sets A and B contain the same number of molecules, while set C does not. Therefore, the set containing the same number of molecules are A and B.
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