Which of the following represents the unit of kinematic viscosity?
cm2/s
Viscosity is a measure of a fluid's resistance to flow. There are two main types of viscosity: dynamic viscosity and kinematic viscosity.
Dynamic viscosity (also known as absolute viscosity) measures the fluid's internal resistance to shear flow. Its dimensions are typically represented as $\left[ \text{Mass} \cdot \text{Length}^{-1} \cdot \text{Time}^{-1} \right]$. Common units include Pascal-second (Pa·s) in the SI system and Poise (P) in the CGS system. One Poise is equal to 1 dyne-second per square centimeter ($\text{dyne} \cdot \text{s/cm}^2$) or 1 gram per centimeter-second ($\text{g/cm} \cdot \text{s}$).
Kinematic viscosity is related to dynamic viscosity and is calculated by dividing the dynamic viscosity by the fluid's density. It represents the fluid's resistance to flow under the influence of gravity. Its dimensions are typically represented as $\left[ \text{Length}^{2} \cdot \text{Time}^{-1} \right]$.
The relationship between kinematic viscosity ($\nu$) and dynamic viscosity ($\mu$) is given by the formula:
$\nu = \frac{\mu}{\rho}$
where $\rho$ is the density of the fluid.
Let's determine the unit of kinematic viscosity by looking at the units of dynamic viscosity and density in common systems:
| Quantity | Symbol | SI Unit | CGS Unit | Dimensions |
|---|---|---|---|---|
| Dynamic Viscosity | $\mu$ | Pa·s (or N·s/m² or kg/(m·s)) | Poise (P) (or dyne·s/cm² or g/(cm·s)) | $\left[ \text{M L}^{-1} \text{T}^{-1} \right]$ |
| Density | $\rho$ | kg/m³ | g/cm³ | $\left[ \text{M L}^{-3} \right]$ |
| Kinematic Viscosity | $\nu$ | m²/s | Stokes (St) (or cm²/s) | $\left[ \text{L}^{2} \text{T}^{-1} \right]$ |
Using the formula $\nu = \mu/\rho$, we can find the unit of $\nu$ in the CGS system:
Let's simplify the unit calculation:
$\frac{\text{g}}{\text{cm} \cdot \text{s}} \div \frac{\text{g}}{\text{cm}^3} = \frac{\text{g}}{\text{cm} \cdot \text{s}} \times \frac{\text{cm}^3}{\text{g}} = \frac{\text{cm}^3}{\text{cm} \cdot \text{s}} = \frac{\text{cm}^2}{\text{s}}$
Thus, the unit of kinematic viscosity in the CGS system is cm²/s. This unit is also known as Stokes (St). A common sub-unit is the centistokes (cSt), where 1 cSt = 1 mm²/s = 10⁻² St.
Let's examine each option to see which one represents the unit of kinematic viscosity:
This is the unit of kinematic viscosity in the CGS system (Stokes).
The dyne is a unit of force in the CGS system ($\text{g} \cdot \text{cm/s}^2$). So, $\text{dyne} \cdot \text{s/cm}^2 = (\text{g} \cdot \text{cm/s}^2) \cdot \text{s/cm}^2 = \text{g/cm} \cdot \text{s}$. This is the unit of dynamic viscosity in the CGS system (Poise).
This unit is $\text{g/(cm} \cdot \text{s})$. As derived above, this is also the unit of dynamic viscosity in the CGS system (Poise). Note that Option 2 and Option 3 represent the same physical unit.
This unit is $\text{g/(cm}^2 \cdot \text{s})$. Let's check its dimensions: $\frac{\text{M}}{\text{L}^2 \cdot \text{T}} = \left[ \text{M L}^{-2} \text{T}^{-1} \right]$. This does not match the dimensions of either dynamic viscosity $\left[ \text{M L}^{-1} \text{T}^{-1} \right]$ or kinematic viscosity $\left[ \text{L}^{2} \text{T}^{-1} \right]$. Therefore, this is not a standard unit of viscosity.
Based on the analysis, the unit representing kinematic viscosity among the options is cm²/s.
| Property | Unit System | Standard Unit | Common Alternative Unit(s) | Related Formula |
|---|---|---|---|---|
| Dynamic Viscosity ($\mu$) | SI | Pa·s (Pascal-second) | N·s/m², kg/(m·s) | $\tau = \mu \frac{du}{dy}$ (Newton's law of viscosity) |
| Dynamic Viscosity ($\mu$) | CGS | Poise (P) | dyne·s/cm², g/(cm·s) | $\tau = \mu \frac{du}{dy}$ |
| Kinematic Viscosity ($\nu$) | SI | m²/s | $\nu = \frac{\mu}{\rho}$ | |
| Kinematic Viscosity ($\nu$) | CGS | Stokes (St) | cm²/s, 100 cSt | $\nu = \frac{\mu}{\rho}$ |
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