The question asks us to identify which number among the given options is divisible by 87. To solve this, we will use the concept of divisibility rules.
The number 87 is a composite number. Its prime factorization is:
$87 = 3 \times 29$
Therefore, a number is divisible by 87 if and only if it is divisible by both 3 and 29.
First, let's apply the divisibility rule for 3 to each option. A number is divisible by 3 if the sum of its digits is divisible by 3.
From this test, we can eliminate options 3 (7150) and 4 (7835). We only need to check options 1 (8004) and 2 (8088) further.
Next, we need to check if the remaining numbers, 8004 and 8088, are divisible by 29. We can perform direct division.
$8004 \div 29$
$8004 = 29 \times 276$
$8088 \div 29$
$8088 = 29 \times 278 + 26$
We summarize our findings:
The only number that satisfies both conditions (divisibility by 3 and 29) is 8004. Hence, 8004 is divisible by 87.
Find the least value of x for which 57x716 is divisible by 9.
Which of the following numbers is NOT divisible by 11?
If 321y72 is a multiple of 6, where y is a digit, what is the least value of y?
From the given numbers A, B, C and D, which number is NOT divisible by 11?
A = 712712
B = 177210
C = 64614
D = 756148
Which of the following numbers is divisible by 7 ?