Which of the following is true about interhalogen compounds?
They are diamagnetic
Interhalogen compounds are neutral molecules that contain two or more different halogen atoms (elements from Group 17 of the periodic table) bonded together. They have the general formulas XX', XX'3, XX'5, and XX'7, where X is the heavier halogen and X' is the lighter halogen.
Let's examine the properties of interhalogen compounds based on the given options:
To determine if interhalogen compounds are diamagnetic or paramagnetic, we need to look at their electronic structure. Halogen atoms all have a valence electron configuration of \(ns^2 np^5\). When they form covalent bonds in interhalogen compounds, they use their valence electrons to form single bonds and also retain lone pairs of electrons.
Consider a simple interhalogen compound like ClF (Chlorine Monofluoride). Chlorine (X) forms one single bond with Fluorine (X'). Chlorine has 7 valence electrons; one is used in the bond, leaving 6 electrons as 3 lone pairs. Fluorine has 7 valence electrons; one is used in the bond, leaving 6 electrons as 3 lone pairs.
All the valence electrons in ClF (both in the bond and as lone pairs) are paired electrons.
Let's look at a more complex example, ClF3 (Chlorine Trifluoride). Chlorine is the central atom. It forms 3 sigma bonds with 3 Fluorine atoms. Chlorine has 7 valence electrons. It uses 3 electrons for bonding. The remaining 4 electrons form 2 lone pairs. Fluorine atoms each form one bond and have 3 lone pairs.
Again, in ClF3, all the valence electrons around the central atom (participating in bonding or as lone pairs) and the terminal atoms are paired. There are no unpaired electrons in the stable molecule.
This holds true for other common interhalogen compounds like BrF5, IF5, IF7, etc. The central halogen atom expands its octet but accommodates the additional electrons as lone pairs and bonding pairs in a way that results in all electrons being paired in the stable molecular structure.
| Compound | Central Atom | Valence Electrons of Central Atom | Bonds Formed | Lone Pairs on Central Atom | Total Electron Groups (Bonds + Lone Pairs) | Paired/Unpaired Electrons |
|---|---|---|---|---|---|---|
| ClF | Cl | 7 | 1 | 3 | 4 | All paired |
| ClF3 | Cl | 7 | 3 | 2 | 5 | All paired |
| BrF5 | Br | 7 | 5 | 1 | 6 | All paired |
| IF7 | I | 7 | 7 | 0 | 7 | All paired |
Since stable interhalogen compounds contain no unpaired electrons, they are diamagnetic. They are repelled by a magnetic field, albeit weakly.
Based on this analysis, the correct statement about interhalogen compounds is that they are diamagnetic.
The element having which of the following electronic configuration will have highest ionization energy?
The shape of the molecule depends on the _______
In Co-ordinate bond, the acceptor atoms must essentially contain in its valency shell an orbital:
The geometrical shape of PCl5 molecules is
Which of the following molecules has T-shaped geometry?