Which of the following is the correct equation for the law of radioactive decay? Symbols have their usual meaning.
N(t) = N0e-λt
Understanding the law of radioactive decay is fundamental in nuclear physics. Radioactive decay is a spontaneous process where an unstable atomic nucleus loses energy by emitting radiation, transforming into a different nucleus or a lower energy state of the same nucleus. The rate at which this decay occurs is described by the law of radioactive decay.
The law of radioactive decay states that the rate of decay of radioactive nuclei at any instant is directly proportional to the number of radioactive nuclei present at that instant. Mathematically, this can be written as:
\begin{equation*}\frac{dN}{dt} \propto N\end{equation*}
Introducing a proportionality constant, \(\lambda\), which is known as the decay constant or disintegration constant, we get:
\begin{equation*}\frac{dN}{dt} = -\lambda N\end{equation*}
The negative sign indicates that the number of nuclei \(N\) decreases with time \(t\).
We can solve this differential equation to find the number of undecayed nuclei \(N(t)\) remaining at any time \(t\). Separating the variables \(N\) and \(t\), we have:
\begin{equation*}\frac{dN}{N} = -\lambda dt\end{equation*}
Integrating both sides from time \(t=0\) to time \(t\) and from the initial number of nuclei \(N_0\) to \(N(t)\):
\begin{equation*}\int_{N_0}^{N(t)} \frac{dN}{N} = \int_{0}^{t} -\lambda dt\end{equation*}
This integration gives:
\begin{equation*}[\ln N]_{N_0}^{N(t)} = -\lambda [t]_0^{t}\end{equation*}
\begin{equation*}\ln N(t) - \ln N_0 = -\lambda (t - 0)\end{equation*}
\begin{equation*}\ln \left(\frac{N(t)}{N_0}\right) = -\lambda t\end{equation*}
To solve for \(N(t)\), we take the exponential of both sides:
\begin{equation*}\frac{N(t)}{N_0} = e^{-\lambda t}\end{equation*}
Thus, the equation for the law of radioactive decay is:
\begin{equation*}N(t) = N_0 e^{-\lambda t}\end{equation*}
Where:
Let's examine the given options in light of the derived law of radioactive decay equation:
Based on the derivation, the correct equation for the law of radioactive decay is \(N(t) = N_0 e^{-\lambda t}\).
| Concept | Description | Formula | Relation to \(\lambda\) |
|---|---|---|---|
| Decay Constant (\(\lambda\)) | Probability of a nucleus decaying per unit time. Unit is s-1 or year-1 etc. | \(\lambda = -\frac{1}{N} \frac{dN}{dt}\) | Fundamental constant for a given isotope. |
| Half-life (\(T_{1/2}\)) | Time taken for half of the radioactive nuclei in a sample to decay. | \(N(T_{1/2}) = N_0 / 2\) | \(T_{1/2} = \frac{\ln 2}{\lambda} \approx \frac{0.693}{\lambda}\) |
| Mean life (\(\tau\)) | Average lifetime of a radioactive nucleus. | Sum of lifetimes / Total number of nuclei | \(\tau = \frac{1}{\lambda}\) |
Related to the number of nuclei is the activity of a radioactive sample, which is the rate of decay. The activity \(A(t)\) at time \(t\) is given by:
\begin{equation*}A(t) = \left|\frac{dN}{dt}\right| = \lambda N(t)\end{equation*}
Substituting the expression for \(N(t)\):
\begin{equation*}A(t) = \lambda (N_0 e^{-\lambda t}) = (\lambda N_0) e^{-\lambda t}\end{equation*}
Let \(A_0 = \lambda N_0\) be the initial activity at \(t=0\). Then the activity equation is:
\begin{equation*}A(t) = A_0 e^{-\lambda t}\end{equation*}
This shows that the activity also decays exponentially with the same decay constant \(\lambda\). Common units for activity include Becquerel (Bq, 1 decay per second) and Curie (Ci, \(3.7 \times 10^{10}\) decays per second).
The radioactive decay process is independent of external factors like temperature, pressure, or chemical environment.
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